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3 years ago

11

Need helppppppCopper sulphate is a crystalline substance. why???

1 answer:

MaRussiya [10]3 years ago

4 0

Explanation:

Copper(II) sulfate, also known as copper sulphate, are the inorganic compounds with the chemical formula CuSO4(H2O)x, where x can range from 0 to 5. The pentahydrate (x = 5) is the most common form. Older names for this compound include blue vitriol, bluestone,[9] vitriol of copper,[10] and Roman vitriol.[11]

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Aqueous sodium phosphate and aqueous iron (III) chloride react to produce aqueous sodium chloride and solid iron (III) phosphate

mojhsa [17]

Answer:

this one is hard

Explanation:

but it's iron because the sodium so yea there u go.

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2 years ago

A disturbance in matter that carries energy from one place to another is called

siniylev [52]

The answer you're looking for is: a wave.

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3 years ago

Please help! Asap! :)

timama [110]

The first one is true.

The second one is false.

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3 years ago

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For the following reaction, 22.0 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas . nitrogen mono

mash [69]

NO is the limiting reagent and 4.34 g is the amount of the excess reagent that remains after the reaction is complete

<h3>What is a limiting reagent?</h3>

The reactant that is entirely used up in a reaction is called as limiting reagent.

The reaction:

$2NO(g) +2H_2(g)$ → $N_2 +2H_2O$

Moles of nitrogen monoxide

Molecular weight: $M_(_N_O_)$ =30g/mol

$n_(_N_O_) =\frac{mass}{molar \;mass}$

$n_(_N_O_) =\frac{22.0}{30g/mol}$

$n_(_N_O_) = 0.73 mol$

Moles of hydrogen

Molecular weight: $M_(_H_2_)$ =30g/mol

$n_(_H_2_) =\frac{mass}{molar \;mass}$

$n_(_H_2_) =\frac{5.80g}{2g/mol}$

$n_(_H_2_) = 2.9 mol$

Hydrogen gas is in excess.

NO is the limiting reagent.

The amount of the excess reagent remains after the reaction is complete.

$n_(_N_2_) =$ (2.9 mol- 0.73 mol NO x $\frac{1 \;mol \;of \;H_2}{2 \;mole \;of \;NO}$ ) x $\frac{2g \;of \;H_2}{mole \;of \;H_2}$

$n_(_N_2_) =$ 4.34 g

Learn more about limiting reagents here:

brainly.com/question/26905271

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5 0

1 year ago

An atom of sodium-23 (Na-23) has a net charge of +1. Identify the number of protons, neutrons, and electrons in the atom. Then,

kolezko [41]

Answer:

Number of proton is 11

Number of neutrons is 12

Number of electrons is 10

Explanation:

For a neutral Na, Sodium atom:

The mass number P+N = 23

Atomic number(E or P) = 11

A charged Na atom that has lost an electron is positively charged and so:

Number of proton = 11 (Still the same)

Number of neutrons = 12

Number of electrons = 11-1=10 (the atom has lost an electron)

If an atom loses electron, it becomes positively charged ie P>E

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3 years ago

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