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Likurg_2 [28]
3 years ago
10

How many moles of methane (CH4) are in 7.31 x 10^25 molecules

Chemistry
2 answers:
Ivan3 years ago
6 0

molar mass of methane CH4

= C + 4 H  

= 12.0 + 4 x 1.008

= 12.0 +  4.032

= 16.042g/mol

7.31 x 10^25 molecules x <u>             1 mole  CH4    </u>  = 121.43 moles

                                       6.02 x 10^23 CH4 molecules

121.43 moles CH4 are present.

       


Alex73 [517]3 years ago
6 0

Answer : The number of moles of methane are, 121.39 moles

Explanation : Given,

Number of molecules of methane gas = 7.31\times 10^{25}

Now we have to calculate the number of moles of methane gas.

As, 6.022\times 10^{23} number of molecules of methane present in 1 mole of methane gas.

So, 7.31\times 10^{25} number of molecules of methane present in \frac{7.31\times 10^{25}}{6.022\times 10^{23}}\times 1mole=121.39 moles of methane gas.

Therefore, the number of moles of methane are, 121.39 moles

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Certain compound contains 7.3% carbon, 4.5% hydrogen, 36.4% oxygen, and 31.8% nitrogen. It’s reality molecular mass is 176.0. Fi
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The answer to your question is:

Explanation:

Data

carbon        7.3%          =     7.3g

hydrogen    4.5%         =      4.5g

oxygen       36.4%         =     36.4 g

nitrogen     31.8%         =     31.8 g

Now

For carbon

                    12 g --------------------1 mol

                    7.3 g     -------------     x

                       x = 7.3/12 = 0.608 mol

For hydrogen

                 1 g   --------------------  1 mol

                 4.5 g  ------------------    x

                   x = 4.5 mol

For oxygen

             16 g ------------------- 1 mol

             36.4 g ----------------    x

             x = 2.28 mol

For nitrogen

              14 g   ----------------   1 mol

              31.8 g ---------------    x

             x = 2.27 mol

Now divide by the lowest result, the is 0.608 from carbon

carbon              0.608/0.608 = 1

hydrogen           4.5/ 0.608 = 7.4

oxygen              2.28/0.608 = 3.75

nitrogen             2.27/0.608 = 3.73

Empirical formula = CH₇O₄N₄

     

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