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Likurg_2 [28]
3 years ago
10

How many moles of methane (CH4) are in 7.31 x 10^25 molecules

Chemistry
2 answers:
Ivan3 years ago
6 0

molar mass of methane CH4

= C + 4 H  

= 12.0 + 4 x 1.008

= 12.0 +  4.032

= 16.042g/mol

7.31 x 10^25 molecules x <u>             1 mole  CH4    </u>  = 121.43 moles

                                       6.02 x 10^23 CH4 molecules

121.43 moles CH4 are present.

       


Alex73 [517]3 years ago
6 0

Answer : The number of moles of methane are, 121.39 moles

Explanation : Given,

Number of molecules of methane gas = 7.31\times 10^{25}

Now we have to calculate the number of moles of methane gas.

As, 6.022\times 10^{23} number of molecules of methane present in 1 mole of methane gas.

So, 7.31\times 10^{25} number of molecules of methane present in \frac{7.31\times 10^{25}}{6.022\times 10^{23}}\times 1mole=121.39 moles of methane gas.

Therefore, the number of moles of methane are, 121.39 moles

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Answer: The space occupied by the gas at 400 torr and 25^{o}C is 250 mL.

Explanation:

Given: V_{1} = 250 mL,    P_{1} = 800 torr,     T_{1} = 50^{o}C

V_{2} = ?,         P_{2} = 400 torr,        T_{2} = 25^{o}C

Formula used is as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{800 torr \times 250 mL}{50^{o}C} = \frac{400 torr \times V_{2}}{25^{o}C}\\V_{2} = 250 mL

Thus, we can conclude that space occupied by the gas at 400 torr and 25^{o}C is 250 mL.

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