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2 years ago

5

Pls help Combustion is commonly referred to as _____.

1 answer:

kati45 [8]2 years ago

7 0

Answer:

Combustion is a chemical reaction in which a substance reacts with air to form energy.

Explanation:

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What energy transformations occur each time the skateboarder rolls up on the ramp? ( I will try to mark you ) (7th grade science

ZanzabumX [31]

Answer:

Kinetic energy is energy of motion. The faster skaters move, the more kinetic energy they have. In a halfpipe, energy is constantly transformed between potential (at the top) and kinetic (as they travel down the sides) as the skater goes back and forth between the ramps.

Explanation:

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3 years ago

A sample of an ideal gas at 1.00 atm and a volume of 1.32 L was placed in a weighted balloon and dropped into the ocean. As the

Amiraneli [1.4K]

Answer:

When the pressure increases to 90.0 atm , the volume of the sample is 0.01467L

Explanation:

To answer the question, we note that

P₁ = 1.00 atm

V₁ = 1.32 L

P₂ = 90 atm.

According to Boyle's law, at constant temperature, the volume of gas is inversely proportional to its pressure

That is P₁V₁ = P₂V₂

Solving the above equation for V₂ we have

$V_2 = \frac{P_1P_2}{P_2}$ that is V₂ = $\frac{1atm*1.32L}{90atm}$ = $\frac{11}{750}L$ or 0.01467L

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3 years ago

Read 2 more answers

The Venus flytrap is a plant that lives in wetland ecosystems that do not have nitrogen-rich soils. To make up for the lack of n

viva [34]

Canivorous plants is the correct answer for your question

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3 years ago

1. When 8 moles of lithium metal react with excess oxygen gas, how many miles of lithium oxide can be produced?

mash [69]

2 moles of lithium oxide

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4 years ago

Read 2 more answers

Consider the reaction of diboron trioxide with carbon and chlorine. B2O3 (s) + 3C (s) + 3Cl2 (g) 2BCl3 (g) + 3CO (g) Determine t

Sholpan [36]

Answer:

Limiting reactant = B2O3

Amount of BCl3 formed = 468 g

Explanation:

The given reaction is:

$B2O3 (s) + 3C (s) + 3Cl2 (g) \rightarrow 2BCl3 (g) + 3CO (g)$

In order to identify the limiting reagent calculate the moles of B2O3, C and Cl2. The reagent with the lowest moles is the limiting reactant

$Moles(B2O3)=\frac{Mass(B2O3)}{Mol.wt(B2O3)}=\frac{139g}{69.6g/mol}=1.997moles$

$Moles(C)=\frac{Mass(C)}{At.wt(C)}=\frac{87.8g}{12g/mol}=7.317moles$

$Moles(Cl2)=\frac{Mass(Cl2)}{Mol.wt(Cl2)}=\frac{650g}{70.9g/mol}=9.168moles$

Since the moles of B2O3 < C < Cl2, the limiting reactant is B2O3

Based on the reaction stoichiometry:

1 mole of B2O3 produces 2 moles of BCl3

Hence, the number of moles of BCl3 produced under the experimental conditions = 2*1.997=3.994 moles

$Mass(BCl3)= Moles* Mol.wt = 3.994 moles*117.17g/mol = 468 g$

8 0

3 years ago