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Angelina_Jolie [31]
3 years ago
9

ASAP pleaseeee and Thankyou​​

Chemistry
1 answer:
Brut [27]3 years ago
7 0
Answer: Mother is bb. Father is Bb
Top left box: Bb
Top Right box: bb
Bottom left box: Bb
Bottom Right box: bb

Hope this helps :D. If you want me to explain my answer just let me know
You might be interested in
The boiling point of water is 100.0°C at 1 atmosphere. How many grams of sodium acetate (82.04 g/mol), must be dissolved in 283.
Alecsey [184]

Answer:

I have to weight 10,04 g of acetate sodium

Explanation:

This is the colligative propertie about elevation of boiling point

ΔT = Kb . m . i  

ΔT is the difference between T° at boiling point of the solution - T° at boiling point of the solvent pure  - we have this data 0,450°C

Kb means ebulloscopic constant (0,52 °C.kg/m .- a known value for water)

m means molality (moles of solute in 1kg of solvent)

i means theVan 't Hoff factor (degree of dissociation for a compound)

For the sodium acetate is 2

NaCH3COO ---> Na+  + CH3COO-

0,450°C = 0,52°C.kg/m . m . 2

0,450°C / (0,52°C.kg/m . 2) = m

0,432 m/kg = m

This number means I have 0,432 moles of acetate sodium, my solute in 1kg of water, my solvent. But I don't have 1000 g (1kg) I only have 283 g so let's make the rule of three:

1000 g _____ 0,432 moles

283 g ______ (283g .0,432m) / 1000g = 0,122 moles

Now that I have the moles of acetate sodium, I have to find the mass.

Moles . molar mass = mass

0,122 moles . 82.04 g/mol = 10,04 g

3 0
4 years ago
Read 2 more answers
Standard reduction half-cell potentials at 25∘c half-reaction e∘ (v) half-reaction e∘ (v) au3 (aq) 3e−→au(s) 1.50 fe2 (aq) 2e−→f
Zanzabum

<em>K</em> = 5.0 × 10^25

<h2>Part (a). Calculate <em>E</em>° for the reaction </h2>

<em>Step 1.</em> Write the equations for the two half-reactions

2H^(+)(aq) + 2e^(-) → H2(g); _0.00 V

Zn^(2+)(aq) + 2e^(-) → Zn(s); -0.76 V

<em>Step 2.</em> Identify the cathode and the anode

The half-cell with the more negative <em>E</em>° (Zn) is the anode.

<em>Step 3.</em> Calculate <em>E</em>°

Zn(s) → Zn^(2+)(aq) + 2e^(-); _________+0.76 V

2H^(+)(aq) + 2e^(-) → H2(g); __________0.00 V

Zn(s) + 2H^(+)(aq) → Zn^(2+)(aq) + H2(g); +0.76 V

<em>E</em>° = +0.76 V

<h2>Part (b). Calculate <em>K</em> for the reaction </h2>

The relation between <em>E</em>° and <em>K</em> is

<em>E</em>° = (<em>RT</em>)/(<em>nF</em>)ln<em>K </em>

where

<em>R</em> = the universal gas constant: 8.314 J·K^(-1)mol^(-1)

<em>T</em> = the Kelvin temperature

<em>n</em> = the moles of electrons transferred

<em>F</em> = the Faraday constant: 96 485 J·V^(-1)mol^(-1)

Then

0.76 V = [8.314 J·K^(-1)mol^(-1) × 298.15 K]/[2 × 96 485 J·V^(-1)mol^(-1)]ln<em>K</em>

0.76 = 0.012 85 ln<em>K</em>

ln<em>K</em> = 0.76/0.012 85 = 59.16

<em>K</em> =e^59.16 = 5.0 × 10^25

4 0
3 years ago
Write the word and balanced chemical equations for the reaction between:
kupik [55]

Answer:

Alumminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3+H2SO4-->Al2(SO4)+6H2O.

Explanation:

plz mark as brainlist

7 0
3 years ago
A certain element exists as two different isotopes. 65.0% of its atoms have a mass of 24 amu and 35.0% of its atoms have a mass
Sauron [17]

Answer:

24.7 amu

Explanation:

An isotope is when an element can have different number of neutrons but they have same number of protons.

In order to calculate the average atomic mass with the given information do the following operations:

First change de percentages to fractional numbers, divide by 100.

I like to make a table, to organize all data and I believe is easier to understand.

65/100 = 0.65

35/100 = 0.35

% fraction

65.0 0.65

35.0 0.35

total100.0 1

Now multiply each mass with their corresponding fraction

24 (0.65) = 15.6

26 (0.35) = 9.1

%    fraction uma uma

65.0 0.65 24 15.6

35.0 0.35 26 9.1

total100.0    1          24.7

Finally you add the resulting mass and the units will be in uma.

15.6+9.1 = 24.7

Therefore the average atomic mass of this element will be 24.7 uma.

Check the table in the document attached

Download xlsx
4 0
3 years ago
A solution contains 35 grams of KNO3 dissolved in 100 grams of water at 40°C. How much more KNO3 would have to be added to make
Marta_Voda [28]

Answer:

32g

Explanation:

potassium nitrate has solubility of about 67g per 100g of water at 40°C, which means that potassium nitrate solution will contain 67g of dissolved salt for every 100g of water.

since at this temperature, our solution contains  35g of potassium nitrate 100g  of water. The solution will be unsaturated because of the less potassium nitrate.

to make saturated solution,

mass of potassuim nitrate = 67g - 35g

= 32g

which means dissolving another  32g  of potassium nitrate in solution at 40 °C will make saturated solution.

5 0
3 years ago
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