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SSSSS [86.1K]
3 years ago
9

3 organisms that help prevent infections

Chemistry
1 answer:
love history [14]3 years ago
8 0

Infection control is the discipline concerned with preventing nosocomial or healthcare-associated infection, a practical (rather than academic) sub-discipline of epidemiology. It is an essential, though often underrecognized and undersupported, part of the infrastructure of health care. Infection control and hospital epidemiology are akin to public health practice, practiced within the confines of a particular health-care delivery system rather than directed at society as a whole. Anti-infective agents include antibiotics, antibacterials, antifungals, antivirals and antiprotozoals.[1]

Infection control addresses factors related to the spread of infections within the healthcare setting (whether patient-to-patient, from patients to staff and from staff to patients, or among-staff), including prevention (via hand hygiene/hand washing, cleaning/disinfection/sterilization, vaccination, surveillance), monitoring/investigation of demonstrated or suspected spread of infection within a particular health-care setting (surveillance and outbreak investigation), and management (interruption of outbreaks). It is on this basis that the common title being adopted within health care is "infection prevention and control." (got from google

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Which category of elements coposes groups 1-12 on the periodic table?
Dimas [21]
I'm pretty sure its metals.
5 0
4 years ago
H
Harman [31]

Answer:c

Explanation: it's easy

7 0
4 years ago
ANDRES MEJIA-C...
BigorU [14]

Explanation:

Gases: more space therefore meaning that particles in the gas have the highest Kinetic energy therefore moving faster all around.

Liquid: they have more kinetic energy than liquid,but they have some space for movement so they collide each other quicker due to lack of space.

solids: They have least kinetic energy as they have no space at all meaning particles can move around and only just vibrate against each other.

3 0
3 years ago
Concentration required to begin precipitate pbcl2 for pbcl2 ksp=1. 17×10−5
Ne4ueva [31]

The concentration required to begin to precipitate PbCl2 for PbCl2 is 0.0216 M.

<h3>What is molarity?</h3>

Molarity is the measure of the concentration of any solute in per unit volume of the solution.

The reaction is \rm Pb^2^+(aq) + 2Cl^-(aq) \rightarrow PbCl_2(s).

The molarity of lead is 0.025 M

The ksp is given 17×10⁻⁵

Now, calculating the concentration

[Pb^2^+] = 0.025 M.\\Ksp = 1.17 \times 10^-^5\\Ksp = [Pb^2^+] \times  [Cl^-]^2\\[Cl^-] =  \dfrac{\sqrt{ Ksp}}{[Pb^2^+]} \\\\[Cl^-] =  \dfrac{\sqrt{ 0.0000117}}{0.025}  \\[Cl^-] = 2.16 \times 10^-^2M.

Thus, the concentration required to begin to precipitate PbCl2 for PbCl2 is 0.0216 M.

Learn more about molarity

brainly.com/question/10725862

#SPJ4

5 0
2 years ago
List at least two chemical reactions that resulted in a white precipitate. For these reactions, list the possible chemical name
earnstyle [38]
Try looking through this, don't actually read it if you don't want to but if you skim through it you might find answers. Good Luck! :) ..Reactions of Aldehydes, Ketones And Phenols Objective: 1. To carry out some simple chemicals test in order to distinguish between aldehydes, ketones and phenols 2. To study the properties of aldehydes, ketones and phenols. 3. To identify the unknowns A, B, C, D and E. Introduction: Part I : Reaction of Aldehydes and Ketones The carbonyl group is C=O and any compound containing this group that can be described as a carbonyl compound. Carbonyl compounds fall into two main classes: aldehydes and ketones on the one hand and carboxylic acids and their derivatives on the other hand. The characteristic reactions of the aldehydes and ketones are addition and oxidation reactions occurring at the unsaturated carbonyl group. With the same reagent, aldehydes usually react faster than ketones, mainly because there is lees crowding at the carbonyl carbon and the steric effect. Aldehydes are also more easily oxidized than ketones. The carbonyl and other compounds investigated in this experiment are tested in each of the following ways: A) Chromic Acid (H2CrO4) Chromic acid is a strong oxidant. Aldehydes are oxidized to carboxylic acids by chromic acid. The Cr6+ in the chromic acid which is orange, then is reduced to Cr3+ which is green/blue. Ketones are not oxidized by chromic acid.image B) Tollen’s Test (Ag(NH3)2+ / OH- Tollen’s reagent (Ag(NH3)2+ / OH- is a weak oxidant. Aldehydes are readily oxidized to carboxylic acids by Tollen’s reagent to produce a silver mirror on the inside of a clean test tube. Ketones are not oxidized by Tollen’s reagent.image C) Fehling’s solution Fehling’s solution is an oxidizing agent. It is prepared by mixing equal part of Fehling’s solution I (copper(II) sulfate) and Fehling’s solution II (sodium potassium tartate and sodium hydroxide). Aldehydes are easily oxidized to carboxylic acid by Fehling’s solution and will reduce the cupric ion which complexed with tartate ion to cuprous oxide. A positive result is indicated by the formation of a brick red precipitate. Ketones are not oxidized by Fehling’s solution.image D) 2,4-dinitrophenylhydrazine (DNP Test or Brady’s Reagent) 2,4-dinitrophenylhydrazine (Brady’s reagent) is an important reagent related to hydrazine. Most aldehydes and ketones very readily with this reagent to give the yellow orange and red precipitates of 2,4-dinitrophenylhydrazones. Unconjugated aldehydes and ketones give precipitates toward the yellow while conjugated compound tend to be deeper colour of red. The conversion of aldehydes and ketones into hydrazone is an example of the addition-elimination reaction occurring at the unsaturated carbonyl group.image E) Iodoform Test Iodoform test can be used for the detection of acetalaldehyde and all methyl ketone which have the formula:image Iodoform, CHI3 is a yellow solid with a strong medicinal smell. Iodoform will precipitate out of a mixture of methyl ketone, iodine and base.image For acetaldehyde, the following reaction shows the formation of iodoform:image Compounds that are easily oxidized to acetaldehyde and methyl ketones also give a positive iodoform test. Only ethanol can be oxidized to acetaldehyde and secondary alcohol that have the general formula CH3CH(OH)R can be oxidized to methyl ketones. Part II: Reactions
5 0
3 years ago
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