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defon
3 years ago
6

A gas made up of homonuclear diatomic molecules escapes through a pinhole times as fast as gas. Write the chemical formula of th

e gas. "0.238"
Chemistry
1 answer:
Art [367]3 years ago
6 0

Answer:

The answer to the question is

Chlorine Cl₂

Explanation:

Graham's Law of effusion states that the rate of effusion of  a gas is inversely proportional to the square root of the molar mass

\frac{R_{1} }{R_{2}} = \sqrt{ \frac{M_{2}}{M_{1}} }

0.238 = \sqrt{ \frac{4}{M_{1}} }

Therefore M₁ = 4÷0.238² = 70.61

Hence the mass of the gas is 70.61, that is X₂ = 70.61  or the molar mass of the element X = 70.61÷2 = 35.308 ≅35.453 Hence the gas is chlorine Cl₂

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The equation for photon energy, E , is
Sidana [21]

The wavelength of a photon that has an energy of E = 3.69×10−19 J is 5.42 x 10⁻⁷ m.

<h3>What do you mean by wavelength?</h3>

The space between corresponding points (adjacent crests) in adjacent cycles is known as the wavelength () of a waveform signal that is sent in space or down a wire.

The wavelength can be calculated by the given formula

E = hc/λ

Where,  E is energy = 3.65 x 10⁻¹⁹ J

h is plank's constant = 6.626 x 10⁻³⁴ J.sec

c is speed of light = 2.9 × 10⁸ m/s

Putting the values in the formula

λ = (6.626 x 10⁻³⁴)(2.9 × 10⁸) / (3.65 x 10⁻¹⁹) = 5.42 x 10⁻⁷ m.

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4 0
2 years ago
When 136g of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezin
loris [4]

The given question is incomplete. The complete question is:

When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.

Answer: The vant hoff factor for sodium chloride in X is 1.9

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=8.2^0C = Depression in freezing point

K_f = freezing point constant

i = vant hoff factor = 1 ( for non electrolyte)

m= molality =\frac{136g\times 1000}{950g\times 75.07g/mol}=1.9

8.2^0C=1\times K_f\times 1.9

K_f=4.32^0C/m

Now Depression in freezing point for sodium chloride is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=20.0^0C = Depression in freezing point

K_f = freezing point constant  

m= molality = \frac{136g\times 1000}{950g\times 58.5g/mol}=2.45

20.0^0C=i\times 4.32^0C\times 2.45

i=1.9

Thus vant hoff factor for sodium chloride in X is 1.9

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2 years ago
How is the mass of 1 mole of an element determined
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One mole (abbreviated mol) is equal to 6.022×1023 molecular entities (Avogadro's number), and each element has a different molar mass depending on the weight of 6.022×1023 of its atoms (1 mole). The molar mass of any element can be determined by finding the atomic mass of the element on the periodic table.
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Which statement best describes how sediment forms?
Anit [1.1K]

Weathering breaks down rock and other material

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Mercury has an atomic number of 80 and a mass number of 200.
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C. The mass number is the amount of Protons and electrons there are combined, so 200 - 80 is 120.
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