Hello!
If i have three moles of a gas at a pressure of 5.6 atm and a volume of 3 liters, what is the temperature ?
We have the following data:
n (number of moles) = 3 moles
P (pressure) = 5.6 atm
V (volume) = 12 L
T (temperature) = ? (in Kelvin)
R (gas constant) = 0.082 atm.L / mol.K
We apply the data above to the Clapeyron equation (gas equation), let's see:
Answer:
The temperature is approximately 205 Kelvin
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I Hope this helps, greetings ... Dexteright02! =)
Answer:
The ricks were degraded over time by wind and water and were crushed down into tiny, smaller rocks, which is sand.
Explanation:
This is my first answer sorry im not that smart
0.250 mol H2 or 0.5 grams H2. Convert your grams to moles (Na 11.2g = 0.5mol | 9g H2O = .5mol) then use your mole ratio (Na / H2 = 2/1 | H2O 2/1) as a proportion to calculate the # of moles produced from each reactant ( 2/1 = .5/x [solve for x]) and then convert your moles (0.25mol H2) to grams using the molar mass of H2 (H[1]x2 = 2) using multiplication. (moles x molar mass) (.250 x 2) to get your answer of 0.5 grams H2
It the exponent! It means how many of them their are