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zysi [14]
3 years ago
7

Someone please help me thank you

Mathematics
1 answer:
Elis [28]3 years ago
4 0

Answer:

x intercept  2

y intercept 1

Step-by-step explanation:

The x intercept is where it crosses the x axis( or horizontal axis)  It crosses at x =2

The y intercept is where it crosses the y axis ( or vertical axis).  It crosses at y =1

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I need help on this math problem ​
abruzzese [7]

Answer:

for the first one, simply add g(x) and h(x) :

x+3 + 4x+1 = 5x + 4

the second one, you would multiply them :

(x+3)(4x+1) = 4x^2 + 13x + 3

the last one, you would subtract :

(x+3)-(4x+1) = -3x + 2

and then substitute 2 for 'x' :

-3*2 + 2 = -6 + 2 = -4

8 0
3 years ago
Read 2 more answers
More Questions! Enjoy!
vladimir1956 [14]

Answer:

1. ?

2. 1/10

3. 1/8

Step-by-step explanation:

number 3 result in decimals is 0.125

7 0
3 years ago
Read 2 more answers
Can someone me with this please?
Phoenix [80]
Number 1 = -6, -1, 3, 7, 11
Number 2 = -4,  -3, -2, 1, 2
Number 3 = 3, 2, 1, 0, -1
Number 4 = -1, 2, 5, 8, 11 
5 0
3 years ago
What is the length of side a?<br><br><br><br><br><br><br><br><br> Thank u
Anna007 [38]
Side a is 13 when using the pythagorean theorem

a^2 + b^2 = c^2
5^2 + 12^2 = c^2
25 + 144 = c^2
c^2 = 169
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4 0
2 years ago
You mix the letters A, C, Q, U, A, I, N, T, A, N, C, and E thoroughly. Without looking, you select one letter. Find P(Q or C) as
Zina [86]

Answer:

P(Q or C) = 0.25

Step-by-step explanation:

We are given the following in the question:

Letters:

A, C, Q, U, A, I, N, T, A, N, C, E

Total number of observations, n  = 12

We have to find the probability that a randomly selected letter is Q or C.

Formula:

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

P(Q or C) =

=\dfrac{\text{n(Q or C)}}{n} = \dfrac{3}{12} =0.25 = 25\%

Thus,

P(Q or C) = 0.25

7 0
3 years ago
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