Item 8
1 answer:
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Answer:
0.082 T
Explanation:
Given:
Frequency of the generator (f) = 60.0 Hz
Maximum emf of the generator (E) = 5200 V
Number of turns (N) = 180
Area per turn (A) = 0.94 m²
Magnetic field magnitude (B) = ?
We know that, the angular frequency of the generator is given as:
Plug in the value of 'f' and solve for 'ω'. This gives,
Now, the maximum emf of the generator is given by the formula:
Rewriting in terms of magnetic field, 'B', we get:
Plug in the given values and solve for 'B'. This gives,
Therefore, the magnitude of the magnetic field in which the coil rotates is 0.082 T.