Answer:
13333.33 rev/min²
Explanation:
Given:
Initial angular speed of the automobile (ω₁) = 1260 rev/min
Final angular speed of the automobile (ω₂) = 3460 rev/min
Time interval for the change in speed (t) = 9.90 s
Angular acceleration of the automobile (α) = ?
Consider the sense of rotation to be positive. So, making use of the equation of motion of rotation, we have:
Rewriting in terms of 'α', we get:
Converting time 't' from seconds to minutes using conversion factor.
1 sec =
So, 9.90 s =
Plug in all the given values and solve for 'α'. This gives,
Therefore, the angular acceleration in revolutions per minute squared is 13333.33 rev/min².
The sliding friction is the net force acting on puck in horizontal direction,
Therefore, from Newton's 2nd law of motion,
f = ma
f = sliding frictional force = μmg
μ =coefficient of sliding friction, m = mass of puck, a = deceleration = 7.8 m/s²
∴ μmg = ma
∴ μ = a/g = 7.8/9.8 = 0.795
Therefore, the coefficient of friction is 0.795
The answer is c. Continuous direct
Answer with Explanation:
We are given that
x=-2.6 cm to x=2.6 cm
Linear charge density=
Length of wire=
Length of wire=
1 m=100 cm
We know that
a.Linear charge density=
Where Total charge =Q
Length=L
Total charge,Q=
Using the formula
Total charge,Q=
b.y=4 cm=
1 m=100 cm
Electric field on the y-axis is given by
Using the formula
c.y=12 cm=
Using the formula
The electromagnetic waves are:
Radio waves
Ultraviolet waves
And Infrared waves
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