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Maslowich
3 years ago
12

A motorboat travels directly east. During its trip, winds blow from directly north, directly south, and southwest. Which of the

following statements is true? A. All of the winds do work on the boat. B. Only the north wind does work on the boat. C. Only the south wind does work on the boat. D. Only the southwest wind does work on the boat.
Physics
1 answer:
denis23 [38]3 years ago
3 0
<span>D. Only the southwest wind does work on the boat. This is because the North and South winds are opposite each other and hence cancel each other out so work is not done.</span>
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A 3 5m container is filled with 900 kg of granite (density of 2400 3 kg m/ ). The rest of the volume is air, with density equal
Elina [12.6K]

Complete question:

A 5-m³ container is filled with 900 kg of granite (density of 2400 kg/m3). The rest of the volume is air, with density equal to 1.15 kg/m³. Find the mass of air and the overall (average) specific volume.

Answer:

The mass of the air is 5.32 kg

The specific volume is 5.52 x 10⁻³ m³/kg

Explanation:

Given;

total volume of the container, V_t = 5 m³

mass of granite, m_g = 900 kg

density of granite, \rho _g = 2,400 kg/m³

density of air, \rho_a = 1.15 kg/m³

The volume of the granite is calculated as;

V_g = \frac{m_g}{ \rho_g}\\\\V_g = \frac{900 \ kg}{2,400 \ kg/m^3} \\\\V_g = 0.375 \ m^3

The volume of air is calculated as;

V_a = V_t - V_g\\\\V_a = 5 \ m^3  \ - \ 0.375 \ m\\\\V_a = 4.625 \ m^3

The mass of the air is calculated as;

m_a = \rho_a \times V_a\\\\m_a = 1.15 \ kg/m^3 \ \times \ 4.625 \ m^3\\\\m_a = 5.32 \ kg

The specific volume is calculated as;

V_{specific} = \frac{V_t}{m_g \ + \ m_a} = \frac{5 \ m^3}{900 \ kg \ + \ 5.32\ kg} = 5.52 \times 10^{-3} \ m^3/kg

4 0
3 years ago
I need help with this question, please
Burka [1]
Ok so this is a kinetic and potential energy problem. KE= 1/2*m*v^2 and PE= mgh so we set them equal to each other and get KE=PE so 1/2mv^2=mgh so mass divers out and left with 1/2v^2 =gh so solving for h or height we get
h=(1/2v^2)/g so h= 1/2*(6.5m/s)^2/9.80m/s^2 = 2.16m in height the ball will reach.

Hope this helps! Any questions please just ask!
Please rate to help me out also! Thank you so much!!!
3 0
3 years ago
Read 2 more answers
Help in question a and b
Mkey [24]
Can you write out the question please? :) Sorry, i don't see it on the paper
8 0
3 years ago
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