take the difference of water levels to find volume of the ring. convert ml to cm3. multiply by density to cancel out cm3 units (idk how to explain that well). you get 8.4g
Answer:
a)this graph is also a line b) in both cases we have a uniform movement
Explanation:
In this exercise we have a uniform movement
v = d / t
d = v t
in the table we give some values to make the graph
t (s) d (m)
1 10
2 20
3 30
In the attached we can see the graph that is a straight line
we have another vehicle at v = 50 me / S
t (s) d (m)
1 50
2 100
3 150
this graph is also a line
b) in both cases we have a uniform movement
<u>A resistor is a passive two-terminal electrical component that implements electrical resistance as a circuit element</u>.
Resistors reduce the current flow and lower voltage levels within circuits.
A <u>circuit is said to be connected in series</u> when the same amount of <u>current flows through the resistors</u>. In such circuits, the voltage across each resistor is different.
In a series connection, if any resistor is broken or a fault occurs, then the entire circuit is turned off. The construction of a series circuit is simpler compared to a parallel circuit.
For the above circuit(attached image-1), the total resistance is given as:
The total resistance of the system is just the total of individual resistances.
A <u>circuit is said to be connected in parallel</u> when the <u>voltage is the same across the resistors</u>. In such circuits, the current is branched out and recombines when branches meet at a common point.
A resistor or any other component can be connected or disconnected easily without affecting other elements in a parallel circuit.
The figure(attached image -2) above shows ‘n’ number of resistors connected in parallel. The following relation gives the total resistance here
The sum of reciprocals of resistance of an individual resistor is the total reciprocal resistance of the system.
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Hope it helps you:)
Answer:
Work done is 882000joule.
power is 29400watt.
Explanation:
given,
Mass(m)=500kg
Acceleration due to gravity(g)=9.8m/s²
Height(h)=6m
Time taken(t)=30s
Workdone=?
Power=?
now,
workdone=force*displaxement
= m*g*h
=500*9.8*6
=8,82,000joule
so, the work done by the man is 8,82,000joule.
then,
power=workdone/time taken
=8,82,000/30
=29,400watt
so, the required power to lift a load is 29,400watt.
Answer:
a toy car was on the floor in the play room until the child applied force by starting to race with it. it accelerated and proceeded to move at 5m/s east. it came to a stop when the bedpost applied force to it.
