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2 years ago

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The driver of a 1000 kg car traveling at a speed of 16.7 m/s applies the brakes. If the brakes provide a force of - 8000 N to st

op the car, how far did the car travel before it stopped

1 answer:

RSB [31]2 years ago

6 0

Answer:

Given:

m=1000kg

u= 16.7m/s

v=0m/s

F=8000N

Required:

s=?

Solution:

F=m × a

8000N=1000kg × a

a=8m/s^2

Since it decelerate a= -8m/s^2

v^2 = u^2 + 2as

s=v^2 - u^2 / 2a

s= 0 - (16.7m/s)^2 / 2 × -8m/s^2

s= -278.89/-16

s= 17.43m

The car travels approximately 17.43m before it stops

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<h3>b) Time</h3>

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$V_{f}=-171.402 m/s$ (10) The negative sign ony indicates the direction is downwards

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Substituting (7) in (2):

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