Answer:
Gasoline
Explanation:
Pure Substance: are those having same type of atoms or molecules.
Compound: one or more atoms of the element combine to form a compound.
Mixture: is combination of one or more substances mix together.
Homogeneous Mixture: are those which are not distinguish by naked eye but can be separated into its components by physical means
Heterogeneous mixture: are those which can be distinguishing by naked eye and can be separated into its components by physical means.
So keeping in mind the above definitions
Table salt:
The chemical formula of table salt is NaCl and it a pure compound not mixture.
Gasoline:
Gasoline is mixture of hydrocarbon, It contains small hydrocarbons ranging from 4 Carbon to 12 Carbon per molecule. it is a homogeneous mixture.
Aluminum:
Aluminum is a pure substance that is made up of same kind of atoms. so it is an element and not mixture. Its symbol is Al
Carbon dioxide:
Carbon dioxide is a pure compound and its chemical formula is CO₂ and not a mixture.
So, the write option is Gasoline.
Answer:
The number of molecules in CH4, also known as methane, is merely 0.85 * 6.02210 * 10 ^ 23 (Avogadro's Number). This amounts to <em><u>approximately 5.1 * 10 ^ 23 molecules</u></em><u> with the correct number of significant figures</u>.
Answer:
0.263M of CH₃COOH is the concentration of the solution.
Explanation:
The reaction of acetic acid (CH₃COOH) with NaOH is:
CH₃COOH + NaOH → CH₃COO⁻Na⁺ + H₂O
<em>1 mole of acetic acid reacts per mole of NaOH to produce sodium acetate and water.</em>
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In the equivalence point, moles of acetic acid are equal to moles of NaOH and moles of NaOH are:
0.0375L × (0.175 moles / L) = 6.56x10⁻³ moles of NaOH = moles of CH₃COOH.
As the sample of acetic acid had a volume of 25.0mL = 0.025L:
6.56x10⁻³ moles of CH₃COOH / 0.0250L =
<em>0.263M of CH₃COOH is the concentration of the solution</em>
Answer:
a) 210.3 g/mol
b) 210.2 g/mol
c) 384.5 g/mol
Explanation:
First step we will calculate the molar masses of ; carbon atom, hydrogen atom and oxygen atom in each .
<u> Molar mass of dibenzyl ketone</u>
Molar mass of dibenzyl ketone = ∑ molar masses of atoms in dibenzyl ketone
= carbon( 15 ) = 15 ( 12.0107 ) + oxygen ( 14 ) = 1 ( 15.999 ) + hydrogen(14) =14(1.00784)
= 210.26926 ≈ 210.3 g/mol
<u> Molar mass of benzil</u>
Molar mass of Benzil = ∑ molar masses of atoms in Benzil
= carbon( 14) = 14(12.0107) + oxygen(2) = 2 ( 15.999) + hydrogen(10) =10(1.00784)
= 210.2262 ≈ 210.2 g/mol
<u>Molar mass of 2,3,4,5-tetraphenylcyclopentadienone</u>
Molar mass = ∑ molar masses of atoms
= carbon ( 29) = 29(12.0107) + oxygen (1) = 1( 15.999 ) + hydrogen(20) = 20(1.00784 )
≈ 384.5 g/mol
Answer:
A.
Explanation:
The leading zeros in c, d, and e are not significant. There is no zero in b. Just one left and all it's zeros are significant.
