3 years ago

A quadratic equation function f(x)=ax^2 passes through (0,0) and (5,5). write an equation for this function

1 answer:

Alex3 years ago

6 0

Equation: f(x)=(1/5)x^2 or f(x)=(0.2)x^2

Check:
f(0)=(1/5)(0)^2
f(0)=(1/5)(0)
f(0)=0✓
f(5)=(1/5)(5)^2
f(5)=(1/5)(25)
f(5)=5✓

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denpristay [2]

Answer:

166.27 m2

Step-by-step explanation:

area of hexagon = $\frac{3*\sqrt{3} }{2}$ * $a^{2}$ where a = length of 1 side

this hexagon is made of 6 equivalent triangle

consider ABC triangle

let AC length be x

AB = 2 * AC = 2x = a

$bc^{2} = ab^{2} - ac^{2} \\(4\sqrt{3})^{2} =(2x)^{2} - x^{2} \\48=3*x^{2}\\ 16=x^{2} \\x=4$

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hence area of hexagon = $\frac{3*\sqrt{3} }{2}$ * $a^{2}$ = $\frac{3*\sqrt{3} }{2}$ * $8^{2}$ = 166.27 m2

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