In a population of mice, the presence of black spots is the result of a homozygous recessive condition. If the frequency of the
allele for this condition is 0.15, what is the approximate percentage of heterozygous genotypes in this mouse population? (Assume that the population is in Hardy-Weinberg equilibrium.) 12%
26%
72%
85%
If A is dominant allele, and a is recessive allel, than:
p is frequency of A allele, q is a frequency of a allele, p2 is a frequency of homozygous dominant genotype, 2pq is frequency of heterozygous genotype and q2 is frequency of homozygous recessive genotype.
If the population is in Hardy-Weinberg equilibrium; p+q=1
The moon's mass is much lower than the earth's; therefore, its gravity isn't strong enough to hold an atmosphere. This lack of an atmosphere and the moon's small size allowed it to become cool enough to the point at which it completely solidified. Thus, the moon doesn't have any plate tectonic activity.
