Answer:
The acceleration of the boxes is 1.5 ft/s²
The displacement of the boxes during the speed-up period is 0.1875 ft.
Explanation:
Hi there!
Let´s convert the 45 ft/min into ft/s:
45 ft/min · 1 min/ 60 s = 0.75 ft/s
It takes the belt 0.5 s to reach this speed. Then, the acceleration of the boxes will be:
a = v/t
Where:
a = acceleration.
v = velocity.
t = time.
a = 0.75 ft/s / 0.5 s
a = 1.5 ft/s²
The acceleration of the boxes is 1.5 ft/s²
The equation of displacement is the following:
x = x0 + v0 · t + 1/2 · a · t²
Where:
x = position of the boxes at time t.
x0 = initial position.
v0 = initial velocity.
t = time.
a = acceleration.
Since the origin of the frame of reference is located at the point where the boxes begin to move, x0 = 0. Since the boxes were initially at rest, v0 = 0. Then:
x = 1/2 · a · t²
x = 1/2 · 1.5 ft/s² · (0.5 s)²
x = 0. 1875 ft
The displacement of the boxes during the speed-up period is 0.1875 ft.
Answer:
the object is decelerating
Answer: 4
Explanation:
when energy is greater then frequency should increase and wavelength should decrease.
Therefore answer is 4
The shape is missing but let's consider it a semi-cylinder attached to the rectangular prism.
Given:
radius = 4.5 mm
<span>Height = 11 mm </span>
<span>Volume of cylinder = (1/2)(pi)(4.5)^2(11) (the shape is divided into half)
V = 349.89 mm cubed
Volume of prism = L x W x H
= 9 x 11 x 6
= 594 mm cubed
Total volume of the composite shape = 111.375 + 594
= 943.89 mm cubed
Rounded answer = 944 mm cubed.</span>
