Answer:
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Answer:
The focal length of the lens in ethyl alcohol is 41.07 cm.
Explanation:
Given that,
Refractive index of glass= 1.500
Refractive index of air= 1.000
Refractive index of ethyl alcohol = 1.360
Focal length = 11.5 cm
We need to calculate the focal length of the lens in ethyl alcohol
Using formula of focal length for glass air system

Using formula of focal length for glass ethyl alcohol system

Divided equation (II) by (I)

Where,
= refractive index of glass
= refractive index of air
= refractive index of ethyl
Put the value into the formula




Hence, The focal length of the lens in ethyl alcohol is 41.07 cm.
Answer:
75k
Explanation:
You can see solution in the picture
Answer:
2,87 * 
Explanation:
When the bullets meet at the center and collide, since momentum is a vectoral quantity, their momentum vectors even up and are sumof zero. Formula of momentum is P = m.v , where m is mass and v is velocity. Let’s name the first two bullets as x,y and the one which mass is unknown as z. Then calculate momentum of x and y:
Px= 5,30 *
* 301 = 1,5953 kg*m/s
Py= 5,30 *
* 301 = 1,5953 kg*m/s
The angle between x and y bullets is 120°, and we know that if the angle between two equal magnitude vectors is 120°, the magnitude of the resultant vector will be equal to first two and placed in exact middle of two vectors. So we can say total momentum of x and y (Px+Py) equals to 1,5953 kg*m/s as well (Shown in the figure).
For z bullet to equalize the total momentum of x and y bullets, it needs to have the same amount of momentum in the opposite way.
Pz = 1,5953 = m * 554
m = 2,87 *
kg