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aleksandr82 [10.1K]
4 years ago
9

What will happen when these two waves interact?

Physics
1 answer:
oee [108]4 years ago
4 0
B would be your answer
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An egg is dropped from a building that is 61 m high.
Allisa [31]

Answer:

Initial Velocity = 0 m/s

Final Velocity = 34.6 m/s

time = 3.5 s

Explanation:

The initial velocity must be zero since, the egg must be at rest initially, before dropping.

<u>Initial Velocity = 0 m/s</u>

Now, for time we use 2nd equation of motion:

h = Vi t + (1/2)gt²

where,

h = Height = 61 m

Vi = Initial Velocity = 0 m/s

g = 9.8 m/s²

t =time = ?

Therefore,

61 m = (0 m/s)(t) + (1/2)(9.8 m/s²)t²

t² = (61 m)(2)/(9.8 m/s²)

t = √(12.45 s²)

<u>t = 3.5 s</u>

Now, for final velocity we will use 1st equation of motion:

Vf = Vi + gt

Vf = 0 m/s + (9.8 m/s²)(3.5 s)

Vf = 34.6 m/s

3 0
3 years ago
What is the density of 25 grams
Karolina [17]

"Density" is the ratio of two numbers ... the mass AND the volume of a piece of some material.

If you only have one number, then the density of it is like one scis, or one tweez, or the sound of one hand clapping, or one pant.

5 0
3 years ago
1. According to Newton's Second Law of Motion, a net force of an object will cause it to accelerate. How does the Newton's law r
Galina-37 [17]
The gravitational field strength creates forces on mass by pulling it towards the centre the equation is weight=mass*gravitational field strength
5 0
3 years ago
Which of the following is a category of mechanical wave?
givi [52]

Answer:

a

because the mechanical wave is when it goes over and over again

8 0
3 years ago
Read 2 more answers
As part of an exercise program, a woman walks south at a speed of 2.00 m/s for 60.0 minutes. she then turns around and walks nor
77julia77 [94]
The woman's average velocity can be calculated by dividing the total distance covered during the motion by the total time of the motion.

In the first part of the motion, the woman moved south with speed v1=2.00 m/s for a time of
t_1 = 60.0 m = 3600 s
therefore the distance she covered is
S=v_1 t_1 = (2.00 m/s)(3600 s)=7200 m

In the second part of the motion, she moved north for S_2 = 3000 m in a time of
t_2 = 25.0 m = 1500 s

Since she moved in the opposite direction, the total distance covered is the difference between S1 and S2:
S=S_1 - S_2 = 7200 m - 3000 m = 4200 m (south)

While the total time of the motion is
t=t_1 + t_2 = 3600 s + 1500 s =5100 s

Therefore, the woman's average velocity is
v= \frac{S}{t}= \frac{4200 m}{5100 s}=0.824 m/s (south)

and the correct answer is A).
5 0
4 years ago
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