What will happen when these two waves interact?

Two resistors are to be combined in parallelto form an equivalent resistance of 400Ω. The resistors are takenfrom available stoc

vivado [14]

Answer:

Δ $R_{e}$ = 84 Ω, $R_{e}$ = (40 ± 8) 10¹ Ω

Explanation:

The formula for parallel equivalent resistance is

1 / $R_{e}$ = ∑ 1 / Ri

In our case we use a resistance of each

R₁ = 500 ± 50 Ω

R₂ = 2000 ± 5%

This percentage equals

0.05 = ΔR₂ / R₂

ΔR₂ = 0.05 R₂

ΔR₂ = 0.05 2000 = 100 Ω

We write the resistance

R₂ = 2000 ± 100 Ω

We apply the initial formula

1 / $R_{e}$ = 1 / R₁ + 1 / R₂

1 / $R_{e}$ = 1/500 + 1/2000 = 0.0025

$R_{e}$ = 400 Ω

Let's look for the error (uncertainly) of Re

$R_{e}$ = R₁R₂ / (R₁ + R₂)

R’= R₁ + R₂

$R_{e}$ = R₁R₂ / R’

Let's look for the uncertainty of this equation

Δ $R_{e}$ / $R_{e}$ = ΔR₁ / R₁ + ΔR₂ / R₂ + ΔR’/ R’

The uncertainty of a sum is

ΔR’= ΔR₁ + ΔR₂

We substitute the values

Δ $R_{e}$ / 400 = 50/500 + 100/2000 + (50 +100) / (500 + 2000)

Δ $R_{e}$ / 400 = 0.1 + 0.05 + 0.06

Δ $R_{e}$ = 0.21 400

Δ $R_{e}$ = 84 Ω

Let's write the resistance value with the correct significant figures

$R_{e}$ = (40 ± 8) 10¹ Ω

6 0

2 years ago

A double charged ion is accelerated to an energy of 32.0 keV by the electric field between two parallel conducting plates separa

Zanzabum

Answer:

$E=8*10^5\frac{V}{m}$

Explanation:

The magnitude of the electric field between two parallel conducting plates is defined as:

$E=\frac{\Delta V}{d}$

Here $\Delta V$ is the potential difference between the plates and d its separation.

The electric potential energy is defined as the product between the particle's charge and the potential difference:

$U=q\Delta V$

Solving for $\Delta V$ and replacing in the electric field formula:

$\Delta V=\frac{U}{q}\\E=\frac{U}{qd}$

In this case we have a double charged ion, so $q=2e$ :

$E=\frac{32*10^3eV}{(2e)(2*10^{-2}m)}\\E=8*10^5\frac{V}{m}$

6 0

2 years ago

A patient has an order for a drug to be infused at the rate of 5 mcg/kg/min. A 500 ml bag contains 250 mg of the drug and the pa

enot [183]

The flow rate is 17gtts/min.

<h3>What is the drug infusion rate?</h3>

The rate of infusion (or dosing rate) in pharmacokinetics refers to the ideal rate at which a drug should be supplied to achieve a steady state of a fixed dose that has been shown to be therapeutically effective. This rate is not only the rate at which a drug is administered.
The infusion volume is divided into drops, which is known as a drip-rate. The Drip Rate formula is as follows: Volume (mL) times time (h) equals drip-rate. A patient must get 1,000 mL of intravenous fluids over the course of eight hours.
Infusion rates of 3–4 mg/kg per minute are advised by manufacturers to reduce rate-related adverse effects. Usually, the infusion lasts for several hours. Although not advised, rates exceeding 5 mg/kg per hour may be tolerated by some patients.
If no negative reactions occur, the rate may be increased in accordance with the table every 30 minutes up to a maximum rate of 3 ml/kg/hour (not to exceed 150 ml/hour).

To find the flow rate is 17gtts/min:

$\frac{18 units}{h} \frac{100ml}{100units} \frac{500ml}{250mg} \frac{1mg}{1000mgc} \frac{20gtts}{ml} =\frac{17gtts}{min}$

Therefore, The flow rate is 17gtts/min.

To learn more about infusion rate, refer to:

brainly.com/question/22761958

#SPJ9

3 0

11 months ago

A basketball is thrown up into the air. It is released with an initial velocity of 8.5 m/s. How long does it take to get to the

ehidna [41]

<h2>It takes 0.867 seconds to get to the top of its motion</h2>

Explanation:

We have equation of motion v = u + at

Initial velocity, u = 8.5 m/s

Final velocity, v = 0 m/s - At maximum height

Time, t = ?

Acceleration , a = -9.81 m/s²

Substituting

v = u + at

0 = 8.5 + -9.81 x t

t = 0.867 s

It takes 0.867 seconds to get to the top of its motion

4 0

2 years ago

Read 2 more answers

A 2-inch, f/4 reflector has a focal length of:

Tema [17]

I’m pretty sure it’s 8 sorry if I’m wrong

5 0

3 years ago