1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
damaskus [11]
3 years ago
7

What is the definition of a reference point

Physics
1 answer:
riadik2000 [5.3K]3 years ago
8 0
A reference point would be something used to understand or judge or describe a certain topic in discussion.
You might be interested in
In an early attempt to understand atomic structure, Niels Bohr modeled the hydrogen atom as an electron in uniform circular moti
AleksandrR [38]

Answer:

The answer is below

Explanation:

Using Coulomb's law of electric field which is:

F=k\frac{q_1q_1}{r^2}\\\\ k =constant=9*10^9\ Nm^2/C^2,q_1=q_2=1.6*10^{-19}C,r=5.29*10^{-11}m\\\\Substituting\ gives:\\\\F=9*10^9*\frac{(1.6*10^{-19})*(1.6*10^{-19})}{(5.29*10^{-11})^2} =8.22*10^{-8}N\\\\Both\ centripetal\ force\ is\ given\ by:\\\\F=m\frac{v^2}{r} \\\\m = mass\ of \ electron=9.11*10^{-31}g,v=speed\ of\ electron\\\\F=m\frac{v^2}{r} \\\\v=\sqrt{\frac{F*r}{m} } \\\\subsituting:\\\\v=\sqrt{\frac{8.22*10^{-8}*5.29*10^{-11}}{9.11*10^{-31}} } \\\\v=2.18*10^6\ m/s\\\\

But\ \omega=\frac{v}{r}=\frac{2.18*10^6}{5.29*10^{-11}}  =4.13*10^{17}\\\\\omega=2\pi f; f=frequency\\\\f=\frac{\omega}{2\pi} =\frac{4.13*10^{17}}{2\pi} \\\\f=6.57*10^{15}\ Hz

6 0
3 years ago
.
Over [174]

Answer:

\boxed {\boxed {\sf 5.22 \ m}}

Explanation:

Gravitational potential energy is the energy an object possesses due to its position. It is calculated using the following formula:

E_P=mgh

Where <em>m</em> is the mass, <em>g</em> is the acceleration due to gravity, and <em>h</em> is the height.

The object has a mass of 8.72 kilograms. Assuming this occurs on Earth, the acceleration due to gravity is 9.8 meters per second squared. The object gains 446 Joules of potential energy.

Let's convert the units of Joules. This makes the process of canceling units simpler later on. 1 Joule is equal to 1 kilogram meter squared per second squared. The object gains 446 J, which is equal to 446 kg *m²/s².

  • EP= 446 kg*m²/s²
  • m= 8.72 kg
  • g= 9.8 m/s²

Substitute the values into the formula.

446 \ kg*m^2/s^2 = 8.72 \ kg * 9.8 \ m/s^2 *h

Multiply on the right side of the equation.

446 \ kg*m^2/s^2 = 85.456 kg*m/s^2 *h

We are solving for the height, so we must isolate the variable h. It is being multiplied by 85.456 kg*m/s². The inverse operation of multiplication is division, so we divide both sides by this value.

\frac{ 446 \ kg*m^2/s^2}{85.456 kg*m/s^2} = \frac{85.456 kg*m/s^2 *h}{85.456 kg*m/s^2}

\frac{ 446 \ kg*m^2/s^2}{85.456 kg*m/s^2} =h

The units of kg*m/s² cancel, leaving meters as our unit.

\frac{ 446 }{85.456 }  \ m =h

5.2190601011 \ m =h

The original measurements of mass and potential energy have 3 significant figures, so our answer must have the same.

For the number we calculated, that is the hundredths place. The 9 in the thousandths place to the right tells us to round the 1 up to a 2.

5.22 \ m \approx h

The object was lifted to a height of approximately <u>5.22 meters.</u>

5 0
3 years ago
during a crash, the acceleration was less than 30g. Calculate the force on a 70 kg person accelerating at this rate.
Igoryamba

Answer:

less than 20580 N

Explanation:

According to the newton's second law of motion

Force = mass * acceleration

(assuming gravitational acceleration =9.8 m/s2 )

acceleration = 30*9.8 = 294 m/s2

acting Force = 70 * 294

                     = 20580 N

Since the acceleration was less than 30g  , acting force should also be less than 20580 N

4 0
3 years ago
A speeding car is pulling away from a police car. The police car is moving at 30 m/s. The radar gun in the police car emits an e
Gekata [30.6K]

Answer:

65.625 m/s

Explanation:

F=20\times 10^9 Hz

\Delta F=F_r-F_t=4750 Hz

c = Speed of light = 3×10⁸ m/s

Relative speed

v=\frac{\Delta F}{2F}\times c\\\Rightarrow v=\frac{4750}{2\times 20\times 10^9}\times 3\times 10^8\\\Rightarrow v=35.625\ m/s

Relative speed = 35.625 m/s

Velocity of speeder = Velocity of police car + Relative speed

⇒Velocity of speeder = 30 + 35.625 = 65.625 m/s

∴ Velocity of speeder is 65.625 m/s

6 0
3 years ago
Your own car has a mass of 2000. Kg if your car produces a force of 5000 N how fast will it accelerate?
Marizza181 [45]
F = m*a
5000 = 2000 * x
5000/2000 = x
2.5 = x
2.5m/s^2 = a


4 0
3 years ago
Other questions:
  • Which model below correctly represents an object with a correct pair of magnetic domains?
    7·1 answer
  • The gravitational force between the Sun (mass -1.99 1030 kg) and Mercury (mass 3.30 x 1023 kg) is 899 1021 N. How far is Mercury
    10·2 answers
  • Shaun is 68 miles away from Keegan. They are traveling towards each other. If Keegan travels 7 mph faster than Shaun and they me
    15·1 answer
  • What is the definition of temperature?
    14·2 answers
  • Blocks A (mass 2.00 kg) and B (mass 6.00 kg) move on a frictionless, horizontal surface. Initially, block B is at rest and block
    11·1 answer
  • Which state of matter has a define shape and definite volume
    5·2 answers
  • Explain the centripetal force or Newton's second law...
    11·2 answers
  • A weightlifter takes 0.5s to raise a barbell with 2 free-weights from the ground to a height of 0.9m. If each free-weight has a
    6·1 answer
  • 6. Suppose the resistance of your body between your right and left hands is 500,000 N. What
    14·1 answer
  • What is diamagnetic materials, paramagnetic materials, ferromagnetic materials?​
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!