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Mnenie [13.5K]
4 years ago
14

I need to know this fairly soon pleaseee​

Mathematics
1 answer:
Elza [17]4 years ago
7 0

Answer:

m<PQT= 94°

Step-by-step explanation:

If line QS bisect <PQR

m<PQS = m < SQR

7x-6= 4x+15

7x-4x= 15+6

3x= 21

X= 21/3

X= 7

m<PQS= 7x-6

m<PQS= 7(7)-6

m<PQS= 49-6

m<PQS= 43°

m<PQS= m<SQR

<mSQR=43°

m<PQR= m<PQS + m < SQR

m<PQR=43+43

m<PQR= 86°

BUT

m<PQR= m<TQW

m<PQT= m<RQW

m<PQR+m<TQW +m<PQT+ m<RQW

= 360°

Let m<TQW= x

86+86+x+x= 360

2x+172= 360

2x= 188

X= 94°

m<PQT= 94°

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The value of tangent theta is equal to the negative 1.  At this value the value of secant theta is \sqrt{2}.

<h3>What is tangent theta?</h3>

The tangent theta in a triangle is the ratio of sine theta and cos theta. It can be written as,

\rm tan\theta=\dfrac{sin \theta}{cos \theta}

Given information-

The value of tangent theta is equal to the negative 1.

\tan \theta=-1

The tangent theta in a triangle is the ratio of sine theta and cos theta. It can be written as,

\rm tan\theta=\dfrac{sin \theta}{cos \theta}

The value of tangent theta is equal to the negative 1. Thus put the value in above expression as,

\rm -1=\dfrac{sin \theta}{cos \theta}\\

Simplify it further as,

\rm -cos \theta=sin \theta

When the value of cosine and sine theta is equal, then the angle exist in 4th quadrant with the value of \dfrac{7\pi}{4}. Which extent to the \sqrt{2}/2 for the cosine function.

In the trigonometry cosine theta is the reciprocal of the secant theta. Thus,

\rm \dfrac{1}{sec\theta}=\dfrac{\sqrt{2}}{2}\\sec\theta=\sqrt{2}

Thus the value of secant theta is \sqrt{2}

Learn more about the tangent theta here;

brainly.com/question/29190

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3 years ago
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3 years ago
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