Answer:
The specific heat of aluminium is 0.8792 J/g °C or 0.21 Cal/g °C
Explanation:
Step 1 : Write formule of specific heat
Q=mcΔT
with Q = heat transfer (J)
with m = mass of the substance
with c = specific heat ⇒ depends on material and phase ( J/g °C)
with ΔT = Change in temperature
For this case :
Q = 1680 Calories = 7033.824 J ( 1 calorie = 4.1868 J)
m = 100.0g
c= has to be determined
ΔT = 100 - 20 = 80°C
<u>Step 2: Calculating specific heat</u>
⇒ via the formule Q=mcΔT
7033.824 J = 100g * c * 80
7033.824 = 8000 *c
c = 7033.824 /8000
c = 0,879228 J/g °C
or 0.21 Cal / g°C
The specific heat of aluminium is 0.8792 J/g °C or 0.21 Cal/g °C
Answer:
Almost 3 snicker's bar will contain the worth of energy stored in the battery which makes option A correct (Fewer than 5)
Explanation:
Step 1
The energy stored in a charged battery is 840 Watt- hours
Recall from the question that 1 KWh = 3600 KJ
So how many Kilo-joules will be in 840 Watt- hours?
I will convert 840 Watt- hours to KWh = 840 / 1000
= 0.840 KWh
Since I KWh gives 3600 KJ
then, 0.840 KWh will give x
x = 3024 KJ
3024 KJ of energy is stored in the battery
Step 2
A snicker bar contains 250 cal and 1 cal = 4.184 KJ
Convert 250 cal to KJ?
250 cal = 1046 KJ
Each snicker bar contains 1046 KJ
To calculate how many snicker's bar worth energy stored in the battery will be (y) ?
y = 3024 / 1046
y = 2.9 snicker's bar approximately 3
The correct option is Fewer than 5
Answer:
Does a fart taste like it smells?
Explanation:
Answer:
Sulfur (S) is an element while the formula for this element is not just sulfur (e.g. H2S, SO2)
Explanation:
Because membrane receptors interact with both extracellular signals and molecules within the cell, they permit signaling molecules to affect cell function without actually entering the cell.
