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Ivenika [448]
2 years ago
7

I don't understand my science usatestprep

Chemistry
2 answers:
just olya [345]2 years ago
8 0

Answer:

OH NO

Explanation:

Just try you best to that's what I do!

Ivahew [28]2 years ago
7 0

Answer: i no rite i dont ether

Explanation:

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The three states of matter are solid, liquid, and gas. true or false
maria [59]
That is True XD
Hope that  helps :D
3 0
3 years ago
I need help with these
Delvig [45]

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9yuigyu need points sorry

Explanation:

4 0
2 years ago
The term “ average atomic mass “ is a ______average so is calculator different Lee from a normal average
hoa [83]

Average atomic mass of an element is a sum of the product of the isotope mass and its relative abundance.

For example: Chlorine has 2 isotopes with the following abundances

Cl(35): Atomic mass = 34.9688 amu; Abundance = 75.78%

Cl(37): Atomic mass = 36.9659 amu; Abundance = 24.22 %

Average atomic mass of Cl = 34.9688(0.7578) + 36.9659(0.2422) =

                                             = 26.4993 + 8.9531 = 35.4524 amu

Thus, the term “ average atomic mass “ is a <u>weighted</u> average so it is calculated differently from a normal average

3 0
3 years ago
Which of the following is a change from a more condensed to a less condensed state of matter?
Alenkasestr [34]
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3 0
3 years ago
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How many number of moles are present in 200. g of sodium bicarbonate (NaHCO3)
nikdorinn [45]

You can solve this problem through dimensional analysis.

First, find the molar mass of NaHCO3.

Na = 22.99 g

H = 1.008 g

C = 12.01 g

O (3) = 16 (3) g

Now, add them all together, you end with with the molar mass of NaHCO3.

22.99 + 1.008 + 12.01 + 16(3) = 84.008 g NaHCO3. This number means that for every mole of NaHCO3, there is 84.008 g NaHCO3. In simpler terms, 1 mole NaHCO3 = 84.008 g NaHCO3.

After finding the molar mass of sodium bicarbonate, now you can use dimensional analysis to solve for the number of moles present in 200. g of sodium bicarbonate.

200. g NaHCO_3 * \frac{1 mole NaHCO_3}{84.008 g NaHCO_3}

Cross out the repeating units which are g NaHCO3, and the remaining unit is mole NaHCO3

200.  * 1 = 200

200/ 84.008 = 2.38

Notice how there are only 3 sig figs in the answer. This is because the given problem only gave three sig figs.

Your final answer is 2.38 mol NaHCO3.

8 0
2 years ago
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