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Stella [2.4K]
3 years ago
6

The number of protons in the nucleus of the atom is equal to the atomic number. True False

Chemistry
2 answers:
fiasKO [112]3 years ago
7 0
Yes it is equal,True 
Dominik [7]3 years ago
6 0
True, <span>The </span>number of protons in the nucleus of the atom is equal to the atomic number<span>. The </span>number of electrons in<span> a neutral </span>atom is equal<span> to the </span>number of protons<span>. The </span>mass number<span> of the </span>atom<span>  is </span>equal<span> to the sum of the </span>number of protons<span> and </span>neutrons in<span> the </span>nucleus<span>.</span>
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Helpl asap nowwww bc i dont understand
dimaraw [331]

Answer: kinetic energy

Explanation: kenitic energey is answer1 Awnser2 potentialand 3 is friction

6 0
3 years ago
Thorium-234 has a half-life of 24.1 days. How many grams of a 150 g sample would you have after 120.5 days?
chubhunter [2.5K]

Answer:

8.625 grams of a 150 g sample of Thorium-234  would be left after 120.5 days

Explanation:

The nuclear half life represents the time taken for the initial amount of sample  to reduce into half of its mass.

We have given that the half life of thorium-234 is 24.1 days. Then it takes 24.1 days for a Thorium-234 sample to reduced to half of its initial amount.

Initial amount of Thorium-234 available as per the question is 150 grams

So now  we start with 150 grams  of Thorium-234

150 \times \frac{1}{2}=24.1

75 \times \frac{1}{2} =48.2

34.5 \times \frac{1}{2} =72.3

17.25 \times \frac{1}{2} =96.4

8.625\times \frac{1}{2} =120.5

So after 120.5 days the amount of sample that remains is 8.625g

In simpler way , we can use the below formula to find the sample left

A=A_{0} \cdot \frac{1}{2^{n}}

Where

A_0  is the initial sample amount  

n = the number of half-lives that pass in a given period of time.

7 0
3 years ago
Curium – 245 is an alpha emitter. Write the equation for the nuclear reaction and identify the product nucleus.
BabaBlast [244]

Answer:

Please find the complete solution in the attached file.

Explanation:

7 0
3 years ago
The mineral enargite is 48.41% cu, 19.02% as, and 32.57% s by mass. what is the empirical formula of enargite?
LuckyWell [14K]
Empirical formula is the simplest ratio of whole numbers of components in a compound. 
Assuming for 100 g of the compound 
                                Cu                                 As                             S
mass                      48.41 g                          19.02 g                      32.57 g
number of moles    48.41 / 63.5 g/mol      19.02 / 75 g/mol        32.57 / 32 g/mol 
                                = 0.762 mol                = 0.2536 mol            = 1.018 mol 
divide by the least number of moles 
                               0.762 / 0.2536             0.2536 / 0.2536         1.018 / 0.2536
                               = 3.00                          = 1.00                         = 4.01
once they are rounded off 
Cu - 3
As - 1
S - 4
therefore empirical formula is Cu₃AsS₄
8 0
3 years ago
Read 2 more answers
Plants and animals that survive in their environment reproduce and pass on their genes. In their turn, their offspring that surv
LiRa [457]
It’s called the Evolution
5 0
3 years ago
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