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DanielleElmas [232]
3 years ago
10

A sundae at an ice-cream shop costs $3, and each extra ounce of toppings costs

Mathematics
1 answer:
anyanavicka [17]3 years ago
7 0

Answer:

The number of ounce of topping that can be get is 4 .

Step-by-step explanation:

Given as :

The cost of a sundae = $3

The cost for each extra ounce of toppings = $0.50

Let The number of ounce of topping = n

The total spending cost on sundae with n extra topping = $5

Now, According to question

The total spending cost on sundae with n extra topping = The cost of a sundae + The number of ounce of topping × The cost for each extra ounce of toppings

Or , $3 + n × $0.50 = $5

or, 3 + 0.50 n = 5

or , 0.50 n = 5 - 3

or, 0.50 n = 2

∴  n = \dfrac{2}{0.50}

I.e n = 4

So, The number of ounce of topping = n = 4

Hence The number of ounce of topping that can be get is 4 . Answer

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3x – 2y = 17 <br> –2x – 5y = 14 <br> Solve using Elimination Please show work
OleMash [197]

Answer:

The solution is x=3 , y=-4 or (3,-4)

Step-by-step explanation:

Given equations (1 and 2) are:

3x- 2y = 17\\-2x -5y = 14

To solve a system of equation with elimination method, the co-efficients of one of the variables has to be equated and then the equations are added or subtracted to get an equation in one variable.

Multiplying equation 1 by 2:

2(3x-2y) = 2*17\\6x-4y = 34\ \ \ \ \ Eqn\ 3

Multiplying equation 2 by 3

3(-2x-5y) = 3*14\\-6x-15y = 42\ \ \ \ Eqn\ 4

Adding equation 3 and 4

(6x-4y) + (-6x-15y) = 34+42\\6x-4y-6x-15y = 76\\-19y = 76\\\frac{-19y}{-19} = \frac{76}{-19}\\y = -4\\

Putting y = -4 in equation 1

3x-2(-4) = 17\\3x+8 = 17\\3x = 17-8\\3x = 9\\\frac{3x}{3} = \frac{9}{3}\\x = 3

Hence,

The solution is x=3 , y=-4 or (3,-4)

3 0
2 years ago
Figure RST on the graph is reflected over the y-axis creating figure R’S’T’. Figure R’S’T’ is translated down 2 units and left 1
Crazy boy [7]

Answer:

RST Is congruent to R’’S’’T’’

Angle R is congruent to angle R prime is congruent to angle R double-prime

TS Is congruent to T’S’ Is congruent to T’’S’’

Step-by-step explanation:

we know that

A reflection and a translation are rigid transformation that produce congruent figures

If two or more figures are congruent, then its corresponding sides and its corresponding angles are congruent

In this problem

Triangles RST, R'S'T and R''S''T'' are congruent

That means

Corresponding sides

RS≅R'S'≅R''S''

ST≅S'T'≅S''T''

RT≅R'T'≅R''T''

Corresponding angles

∠R≅∠R'≅∠R''

∠S≅∠S'≅∠S''

∠T≅∠T'≅∠T''

therefore

RST Is congruent to R’’S’’T’’

Angle R is congruent to angle R prime is congruent to angle R double-prime

TS Is congruent to T’S’ Is congruent to T’’S’’

3 0
3 years ago
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the answer is a hope this help

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