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pogonyaev
4 years ago
7

A 50.0-kg crate is being pulled along a horizontal smooth surface. The pulling force is 10.0 N and is directed 20.0° above the h

orizontal. What is the magnitude of the acceleration of the crate?a. 250 N, 0.0684 m/s²
b. 487 N, 0.188 m/s²
c. 525 N, 0.200 m/s²
d. 825 N, 0.376 m/s²
e. 494 N, 0.0728 m/s²
Physics
1 answer:
Sonbull [250]4 years ago
5 0

Answer:b-0.188 m/s^2

Explanation:

Given

mass of crate m=50 kg

Magnitude of friction F=10 N

Inclination of Force \theta =20^{\circ}

Force cos component will move the Block

F_{net}=F\cos \theta =ma

a=\frac{10\cos 20}{50}

a=0.188 m/s^2

 

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Ball X of mass 1.0 kg and ball Y of mass 0.5kg travel toward each other on a horizontal surface. Both balls travel with a consta
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Answer:

B. Ball Y will travel at a speed less than 5 m/s in the opposite direction of travel as before the collision.

Explanation:

Impulse created by ball Y  on ball X = 40 x 1/6 Ns

Ball X will also create impulse 40 / 6 on ball Y .

impulse = change in momentum .

impulse in Y = change in momentum in Y .

Initial momentum of Y  = .5 x 5 = 2.5

Let final velocity of Y after collision be v  in opposite direction .

change in momentum of Y = v - (-2.5 )

so,

v + 2.5 = 40 / 6 =  6.67

v =  4.17 m / s .

Option B is correct .

B. Ball Y will travel at a speed less than 5 m/s in the opposite direction of travel as before the collision.

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Approximately, What is the value of the Hubble Constant, as measured by scientists? Hypothetically, if the value of the Hubble C
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Answer:

The current value of the Hubble's constant = 73 km/sec/Mpc.

t = 71.9 trillion years will be the new age of universe if the Hubble constant = 700 km/s/Mpc

Explanation:

The current value of the Hubble's constant = 73 km/sec/Mpc. However, recent discoveries in the cosmology contradicts the idea of Hubble constant as being fixed. Some scientists are not agreeing on this value and the debate is going on.

Hubble law states that how fast universe is expanding or in other words, galaxies are expanding separating with a speed directly proportional to the distance of galaxies to the earth.

Hence,

v is directly proportional to d

where, v = apparent velocity

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if we equate velocity and distance then there comes Hubble constant.

v = H_{0} x d

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where, Mpc = Mega Parsec = 1 Mpc = 3.086 x 10^{19} km      

We can use Hubble constant to tell the age of universe.

t = d/v

t = d/( H_{0} xd)

t = 1/H_{0}

Scientist calculated the age of universe by using Hubble constant, which is 13.4 billion years.

Now, if we hypothetically change the value of Hubble constant,

from H_{0} = 73 km/sec/Mpc to H_{0} = 700 km/sec/Mpc

then the age of universe will be:

t = 1/H_{0}

first convert the units of new H_{0} into 1/s

H_{0} = (700) x (/3.08 x 10^{19} )

H_{0} = 227.27 x10^{-19}  = 2.27 x 10^{-21} 1/s

So,

Age of universe will be:

t = 1/H_{0} = 1/2.27x10^{-21} 1/s

t = 2.27 x 10^{21} s

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A very long, uniformly charged cylinder has radius R and linear charge density λ. Find the cylinder's electric field strength ou
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The cylinder's electric field magnitude, at a distance <em>r</em> from the axis of the cylinder (greater than the cylinder's radius), is equal to E= \frac{\lambda}{2\pi \epsilon_0 \cdot r}

<h3>Further explanation</h3>

Matter is the building block of everything that we encounter in our lives. Matter is made of atoms, which are in turn made of tiny particles which are called electrons, protons, and neutrons. The ammount of these 3 elements, and their topological configuration in the atoms, is what determines what a certain element is (like Carbon, Hydrogen, Iron, etc).

In some cases, some elements may lose or gain some electrons. Regarded that this missing or extra electrons are not very high in number, the material doesn't lose any of its properties, however it will always try to get its number of electrons back to normal. This is when we say that an element has a <em>charge</em>, which is a measure of how much electrons a body needs to get back to normal. A body has positive charge if it lacks electrons, and has negative charge if it has extra electrons.

This charge causes the material to have an Electric field, which is a measure of how much does it attract or repel electrons. In the case of our problem, we need to compute exactly that, the Electric field. In our problem, we have an infinitely long cylinder with a linear charge density \lambda, this means that all parts of the cylinder have the same charge, and due to symmetry, the electric field is constant on the angular and longitudinal directions of the cylinder.

This makes easy to apply Gauss' Law, since for a Gaussian curve in the shape of a concentric cylinder (with a higher radius than that of our charged cylinder) we can write:

\Phi = \frac{\lambda \cdot L}{\epsilon_0}

Where \Phi is called the Electric flux. Since the electric field is constant for a given distance <em>r</em> from the axis of the cylinder we can write that:

\Phi = E \cdot 2\pi r \cdot L

Joining both our expressions we can get that:

E= \frac{\lambda}{2\pi \epsilon_0 \cdot r}

<h3 /><h3>Learn more</h3>
  • Description on Electric fields: brainly.com/question/8971780
  • Relation between electric fields and magnetism: brainly.com/question/2838625
  • How can we use electric charges: brainly.com/question/10427437
<h3>Keywords</h3>

Electrons, protons, electric field, cylinder, electric flux

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