<span>At constant temperature and moles, the answer can simply becomes P1V1 = P2V2. The original sample is 760 torr and 5.00 l, and was then compressed to 3.00 l. (760 torr)(5.00 l ) = (3.00 l)(X torr), X = 1270 torr. The new pressure exerted by helium on its container is 1270 torr.</span>
Scientists use Scientific notation
This is an exercise in the general or combined gas law.
To start solving this exercise, we obtain the following data:
<h3>
Data:</h3>
- T₁ = 22.5 °C + 273 = 295.5 K
- P₁ = 1.95 atm
- V₁ = ¿?
- P₂ = 3.69 atm
- T₂ = 11.9 °C + 273 = 284.9 k
- V₂= 56.4 ml
We use the following formula:
P₁V₁T₂ = P₂V₂T₁ ⇒ General formula
Where
- P₁ = Initial pressure
- V₁ = Initial volume
- T₂ = Initial temperature
- P₂ = Final pressure
- V₂ = final volume
- T₁ = Initial temperature
We clear the formula for the initial volume:

We substitute our data into the formula to solve:



The helium-filled balloon has a volume of <u>110.697 ml.</u>
Answer:
Carbon Prefix Structure
1 Methane CH4
2 Ethane CH3CH3
3 Propane CH3CH2CH3
4 Butane CH3(CH2)2CH3
5 Pentane CH3(CH2)3CH3
6 Hexane CH3(CH2)4CH3
7 Heptane CH3(CH2)5CH3
8 Octane CH3(CH2)6CH3
9 Nonane CH3(CH2)7CH3
10 Decane CH3(CH2)8CH3
11 Undecane CH3(CH2)9CH3
12 Dodecane CH3(CH2)10CH3
Explanation: