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monitta
3 years ago
15

A 2.0 mL sample of a liquid has a mass of 44.0 g. What is the density of the liquid?

Chemistry
1 answer:
riadik2000 [5.3K]3 years ago
8 0

Answer:

The answer is

<h2>22 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}

From the question

mass of liquid = 44 g

volume = 2 mL

The density of the liquid is

density =  \frac{44}{2}

We have the final answer as

<h3>22 g/mL</h3>

Hope this helps you

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What volume did a helium-filled balloon have at 22.5 c and 1.95 atm if it’s new volume was 56.4 mL at 3.69 atm and 11.9c
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This is an exercise in the general or combined gas law.

To start solving this exercise, we obtain the following data:

<h3>Data:</h3>
  • T₁ = 22.5 °C + 273 = 295.5 K
  • P₁ = 1.95 atm
  • V₁ = ¿?
  • P₂ = 3.69 atm
  • T₂ = 11.9 °C + 273 =  284.9 k
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We use the following formula:

P₁V₁T₂ = P₂V₂T₁ ⇒ General formula

Where

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  • V₁ = Initial volume
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  • V₂ = final volume
  • T₁ = Initial temperature

We clear the formula for the initial volume:

\boldsymbol{\sf{V_{1}=\dfrac{P_{2}V_{2}T_{1}}{P_{1}T_{2}}  } }

We substitute our data into the formula to solve:

\boldsymbol{\sf{V_{1}=\dfrac{(3.69 \not{atm})(56.4 \ ml)(295.5 \not{k})}{(1.95 \not{atm})(284.9\not{k})}  }}

\boldsymbol{\sf{V_{1}=\dfrac{61498.278}{555.555} \ lm }}

\boxed{\boldsymbol{\sf{V_{1}=110.697 \ lm }}}

The helium-filled balloon has a volume of <u>110.697 ml.</u>

6 0
1 year ago
Read 2 more answers
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2         Ethane        CH3CH3

3         Propane   CH3CH2CH3

4         Butane   CH3(CH2)2CH3

5         Pentane  CH3(CH2)3CH3

6         Hexane   CH3(CH2)4CH3

7         Heptane   CH3(CH2)5CH3

8         Octane    CH3(CH2)6CH3

9         Nonane     CH3(CH2)7CH3

10        Decane      CH3(CH2)8CH3

11        Undecane     CH3(CH2)9CH3

12       Dodecane     CH3(CH2)10CH3

Explanation:

7 0
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