Acetone (systematically named propanone)
28. unbalanced because in reactant side the Aluminium is 1 and oxygen is 2 but in the product side the Aluminium is 2 and oxygen is 3 it is not equal so it is unbalanced equation
29. unbalanced because the oxygen atom are not equal in the reactant and the product side
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The normality that would be calculated will be to high because the change in volume will be greater than the actual change in volume. if the buret tip is not filled when reading the initial volume, the actual volume should be lesser with that reading. so if you will you the higher reading the change in volume or the volume you use in titration will be higher than the actual
Answer:
6.2 × 10^-2
Explanation:
Given the reaction:
------------2N2O(g) N2H4(g) <---> 3N2(g) 2H2O(g)
Initial: N2O = 0.1, N2H4 = 0.25-- 0 - - - - - 0
Then: N20 = -2x, N2H4= - x - - - +3x, +2x
Equ : 0.1 - 2x ; 0.25 - x ; +3x ; +2x
At equilibrium :
Add both:
N2O = 0.1 - 2x ;
N2H4 = 0.25 - x;
3N2 = 3x
2H2O = 2x
Moles of N2O at equilibrium = 0.059
Then;
0.1 - 2x = 0.059
-2x = 0.059 - 0.1
-2x = - 0.041
x = 0.041 / 2
x = 0.0205
Moles of N2 present at equilibrium ;
3N2 = 3x
3N2 = 3(0.0205)
= 0.0615
= 0.062 = 6.2 × 10^-2