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ruslelena [56]
3 years ago
14

PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE H

ELP PLEASE HELP
CHEMISTRY MOLE CONVERSIONSS!!! DUE IN 15 MINS PLEASE HELP ANYBODY!! PLZ DONT ANSWER IF U DONT KNOW!

Chemistry
1 answer:
vfiekz [6]3 years ago
6 0

Answer:

AU9NJ-BLVHV-TCLJS-54YTB

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At 25°C, 100 g of water will be saturated with 35.7 g of NaCl. Which word below describes the solution of 1.55 mol of NaCl disso
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1) The saturation point at 25°C is 35.7 g of NaCl / 100 g of water => 35.7 %

Under normal circumstances water will not accept more salt than that.

2) The solution with 1.55 mol of NaCl dissolved in 250 mL of water =>

molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol

grams of NaCl = 1.55 mol * (molar mass of NaCl) = 1.55mol * 58.44 g/mol = 90.58 grams of NaCl


grams of water = 250 mL * 1 g/mL = 250 g/g.

Concentration of the solution:  [90.58 g NaCl / 250 g H2O] * 100 = 36.23 %

3) Conclusion: the solution has more salt than the saturation value. This means that the solution is supersaturated.

Supersaturation is a special condition, which is unstable, but that is not part of the questions.

The answer is supersaturated, 
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