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WITCHER [35]
3 years ago
10

Type in the name of the following compounds. Be sure to use the periodic table if needed.

Chemistry
2 answers:
Snowcat [4.5K]3 years ago
8 0

the answer is Sulfur dioxide

Sauron [17]3 years ago
3 0

Answer:

Sulfur Dioxide

Explanation:

hope this helps:)

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Calculate the specific heat capacity of aluminum if 14,200 J of heat is released in cooling a 350.0
andrew-mc [135]

Answer:

                     Specific Heat Capacity  =  0.901 J.g⁻¹.°C⁻¹

                     Heat is Exothermic

Explanation:

                     Specific heat capacity is the amount of heat required to raise the temperature of a given amount of substance by one degree.

Also, Exothermic reactions are those reaction in which the heat is lost from the system to surrounding while, endothermic reactions are those in which the system gains heat from the surroundings.

The equation used for this problem is as follow,

                                                 Q  =  m Cp ΔT   ----- (1)

Where;

           Q  =  Heat  =  14200 J

           m  =  mass  =  350 g

           Cp  =  Specific Heat Capacity  =  ??

           ΔT  =  Change in Temperature  =  70 °C  -  25 °C  =  45 °C

Solving eq. 1 for Cp,

                                Cp  =  Q / m ΔT

Putting values,

                                Cp  =  14200 J / (350 g × 45 °C)

                                Cp  =  0.901 J.g⁻¹.°C⁻¹

As the heat is lost by the metal therefore, the heat is exothermic.

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3 years ago
Que tipo de mistura tem a agua mineral?
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mezcla homogénea

El agua en sí es un ejemplo de mezcla homogénea. Todo el agua, excepto la más pura, contiene minerales y gases disueltos. Estos se disuelven en todo el agua, por lo que la mezcla se presenta en la misma fase y es homogénea.

6 0
2 years ago
The final volume of the solution is 284 mL. What is the concentration of CuSO4 in the final solution, in mol/L?
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Answer:

0.0252mol/L

Explanation:

The following data were obtained obtained from the question:

Volume of solution = 284mL = 284/1000 = 0.284L

Mole of CuSO4 = 7.157 × 10^-3 mol

Molarity =?

Molarity = mole/Volume

Molarity = 7.157x10^-3 /0.284

Molarity = 0.0252mol/L

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