$a_{n} \: = \: 2(a_{n - 1})^{2} \\ a_{1} = 4 \: (given) \\ a_{2} = \: 2(a_{2 - 1})^{2} \\ = 2(a_{ 1})^{2} \\ = 2 \times {4}^{2} \\ = 32 \\ \\ a_{3} = \: 2(a_{3 - 1})^{2} \\ = 2(a_{ 2})^{2} \\ = 2 \times {32}^{2} \\ = 2 \times 1024 \\ = 2048$

so first 3 terms are

4, 32, 2048

8 0

3 years ago

Read 2 more answers

Evaluate 15 + |-3| - 4

hichkok12 [17]

Answer:

Step-by-step explanation:

we are solving 15 + |-3| - 4

anything inside | | means it's absolute value.

absolute value means that even if it is a negative number inside, it will change to positive. if it is a positive number inside, it will stay the same.

so |-3| is 3.

15 + 3 - 4

18 - 4 = 14.

we got the answer

6 0

2 years ago

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What is the interquartile range of a data set? <br> what does the IRQ tell you about a data set?

Naddik [55]

Answer:

I would help you... But I think that you are supposed to have a picture and there is no picture.

4 0

3 years ago

How do you evaluate 3ab

dimaraw [331]

Lets say a=2 and b=5 you now plug in you numbers to get 3x2x5 we know 3x2=6 so now take 6 and multiply it by 5 so 6x5=30 you can also set this equal to 0 3ab=0 then divide by either a or b ill show you both if you divide by a you are left with 3b=a if you divide by b than you get 3a=b

5 0

2 years ago