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adoni [48]
3 years ago
5

Write a problem to describe the number line. plzz help

Mathematics
1 answer:
suter [353]3 years ago
6 0

Answer:

-1-(-3)

Step-by-step explanation:

hope this helps

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Is ( − 3,2 ) a solution of -4x - 10y &lt; -9?<br><br>Yes or no
yanalaym [24]

Replace x and y in the equation with the given point and solve:

-4(-3) - 10(2) = 12 -20 = -8

-8 is not less than -9

(-3,2) is not a solution.

4 0
3 years ago
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7,000 mg = how many grams
Gnom [1K]
7 grams. 1,000 mg is equivalent to one gram.
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3 years ago
$3 for 6 bagels; $9 for 24 bagels.Determine if the rates or ratios are equivalent
Luba_88 [7]
No these are not equivelent.  24 is 4x6 so that would mean that you would have to pay $12 for those bagels and because 9 is not 3x4, 12 is making these two ratios not equivelent.

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4 years ago
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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
lord [1]

Given : A florist currently makes a profit of $20 on each of her celebration bouquets and sells an average of 30 bouquets every week . and graph

To Find :  Maximum profit , breakeven point , profit interval

Solution:

The maximum profit the florist will earn from selling celebration bouquets is $ 675

peak of y from Graph

The florist will break-even after  Selling 20     one-dollar decreases.

at breakeven

Break even is the point where the profit p(x) becomes 0

The interval of the number of one-dollar decreases for which the florist makes a profit from celebration bouquets is (0 ,20).

after 20 , P(x) is - ve

3 0
3 years ago
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F(x)= -x over x^2+5 on the domain [0,4]
BartSMP [9]
If you're asking for extrema, like the previous posting

well

\bf f(x)=\cfrac{-x}{x^2+5}&#10;\\\\\\&#10;\cfrac{df}{dx}=\cfrac{(x^2+5)+2x^2}{(x^2+5)^2}\implies \cfrac{df}{dx}=\cfrac{5+3x^2}{(x^2+5)^2}\impliedby &#10;\begin{array}{llll}&#10;using\ the\\&#10;quotient\ rule&#10;\end{array}

like the previous posting, since this rational is identical, just that the denominator is negative, the denominator yields no critical points

and the numerator, yields no critical points either, so the only check you can do is for the endpoints, of 0 and 4

f(0) = 0        <---- only maximum, and thus absolute maximum

f(4) ≈ - 0.19  <----  only minimum, and thus absolute minimum
5 0
3 years ago
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