Answer:
450.0 L.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and T are constant, and have different values of P and V:
<em>(P₁V₁) = (P₂V₂).</em>
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V₁ = 760.0 L, P₁ = 450.0 mm Hg,
V₂ = ??? L, P₂ = 760.0 mm Hg (standard pressure = 1.0 atm = 760 mm Hg).
∴ V₂ = (P₁V₁)/(P₂) = (760.0 L)(450.0 mm Hg)/(760.0 mm Hg) = 450.0 L.
Answer:
1.93
Explanation:
Moles of C
H
COOH = 38/1000 × 0.50 = 0.019mol
Moles of CHCOONa = Mass/Molar mass = 2.64/144.10 = 0.018321mol
Final pH = pKa + log([CHCOONa]/[CHCOOH]
= -log Ka + log(mols of CHCOONa]/mols of CHCOOH
= -log(6.5 × 10^(-5)) + log (0.018321/0.019)=4.17
change in pH = final - initial pH
= 4.17 - 2.24
=1.93
Answer:
A.
Explanation:
A decomposition reaction is when one reactant (the substances to the left of the arrow in the reaction) breaks apart into two or more products (the substances to the right of the arrow).
Because KClO3 is breaking down into KCl and O2, it's a decomposition reaction.
Answer:
Explanation:
find solution in the attached below
