Answer:
Lithium Chloride would be the best one
Sodium Hydroxide would be the second best
Explanation:
Alkali metals, Alkaline Earth metals, Transition metals, Basic metals, semi metals or metalloids, Non-metals, Halogens, Noble gases, Lanthanides and Actinides.
The answer to your question is letter C. Accounts Receivable
Bone age : 22,920 years
<h3>Further explanation</h3>
Given
Nt = 2.5 g C-14
No = 40 g
half-life = 5730 years
Required
time of decay
Solution
General formulas used in decay:
![\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}](https://tex.z-dn.net/?f=%5Clarge%7B%5Cboxed%7B%5Cbold%7BN_t%3DN_0%28%5Cdfrac%7B1%7D%7B2%7D%29%5E%7Bt%2Ft%5Cfrac%7B1%7D%7B2%7D%20%7D%7D%7D)
t = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
Input the value :
![\tt 2.5=40.\dfrac{1}{2}^{t/5730}\\\\\dfrac{2.5}{40}=\dfrac{1}{2}^{t/5730}\\\\(\dfrac{1}{2})^4=\dfrac{1}{2}^{t/5730}\\\\4=t/5730\rightarrow t=22920~years](https://tex.z-dn.net/?f=%5Ctt%202.5%3D40.%5Cdfrac%7B1%7D%7B2%7D%5E%7Bt%2F5730%7D%5C%5C%5C%5C%5Cdfrac%7B2.5%7D%7B40%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5E%7Bt%2F5730%7D%5C%5C%5C%5C%28%5Cdfrac%7B1%7D%7B2%7D%29%5E4%3D%5Cdfrac%7B1%7D%7B2%7D%5E%7Bt%2F5730%7D%5C%5C%5C%5C4%3Dt%2F5730%5Crightarrow%20t%3D22920~years)