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puteri [66]
3 years ago
13

Give the coordination number of the central metal ion in the following complex ions.

Chemistry
1 answer:
melomori [17]3 years ago
8 0

Answer:

a). Coordination no. of [Ni(en)_2(NH_3)_2]^2+ = 6

b). Coordination no. of [Fe(en)(ox)Cl_2]^2- = 6

Explanation:

Coordination number is defined as number of donar atoms bonded to the central atom of the complex ion.

a). Coordination no. of [Ni(en)_2(NH_3)_2]^2+ = 6

en or ethylenediamine is a bidentate ligand.

In bidentate ligand, two atoms directly bonded to the central atom.

NH3 is a unidentate ligand.

So, coordination no.= No. of bidentate ligand x 2 + No. of unidentate ligand

                                = 2\times 2 + 2 = 6

b). Coordination no. of [Fe(en)(ox)Cl_2]^2- = 6

Ethylenediamine (en) is a bidentate ligand.

oxalate ion (ox) is also a bidentate ligand.

Cl is a unidentate ligand

So, coordination no.= No. of bidentate ligand x 2 + No. of unidentate ligand

                                = 2\times 2 + 2 = 6

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Elanso [62]

Answer:

1.55×10²² molecules.

Explanation:

We'll begin by calculating the number of mole in 5.32 g of pure lead (Pb). This can be obtained as follow:

Mass of Pb = 5.32 g

Molar mass of Pb = 207 g/mol

Mole of Pb =?

Mole = mass /molar mass

Mole of Pb = 5.32/207

Mole of Pb = 0.0257 mole

Finally, we shall determine the number of molecules in 0.0257 mole of Pb. This can be obtained as follow:

From Avogadro's hypothesis,

I mole of Pb contains 6.02×10²³ molecules.

Therefore, 0.0257 mole will contain = 0.0257 × 6.02×10²³ = 1.55×10²² molecules.

Therefore, 5.32 g of pure lead (Pb) contains 1.55×10²² molecules.

4 0
3 years ago
9. What type of bond is pictured in the image below?
mestny [16]

Answer:

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If a man has a mass of 83 kilograms on Earth, what will the force of gravity on his body be on the moon? A. 135.6 N B. 318.5 N C
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A is the closest choice.
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I think its gas i forgot
6 0
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Consider the reaction.
Alex_Xolod [135]

Note the signs of equilibrium:-

  • Reaction don't procede forward or backward
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So

if

Concentration of A is 2M then concentration of B should be same .

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