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Aleks [24]
2 years ago
11

1. Shankar and Sameer performed an experiment to differentiate primary, secondary and tertiary amines in a laboratory.Shankar co

rrectly identified those 3 compounds but Sameer could only identify primary amine. a) What may be the reagent used by Sameer 1) Ammonical Silvernitrate solution 2) Chloroform & Caustic potash 3) Aqueous Copper Sulphate solution
Chemistry
1 answer:
lesya [120]2 years ago
3 0

Answer: 2) Chloroform & Caustic potash

Explanation:

The carbylamine reaction is a kind of chemical test which is done to detect primary amines in an unknown solution. It cannot detect secondary and tertiary amines.

The reaction involves the heating with up of the unknown solution with alcoholic potassium hydroxide or caustic potash and the chloroform.

In the presence of primary amine, the production of isocyanide results.

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A substance that increases the concentration of hydroxide ions in aqueous solution.
stepladder [879]
The answer that complete the sentence is "Arrhenius base".

The complete sentence is: A substance that increases the concentration of hydroxide ions in aqueous solution is an Arrhenius base.

Arrhenius' acid and base model says that an acid is a substance that contains hydrogen and ionizes in aqueous solution producing protons (H+) and a base is a substance that cointains hydroxide and release it in aqueous solution.
5 0
3 years ago
How many weeks does it take for one full moon to go to the next full moon
OlgaM077 [116]
4 weeks for the moon to go to the next full moon 

8 0
3 years ago
Read 2 more answers
John rode 3150 m at an average speed of 350 m/min.If he had ridden at average of 375 m/min instead. How much sooner would it hav
Svet_ta [14]

Explanation:

Given that:

Distance traveled = 3150m

Average speed = 350m/min

Suggested speed = 375m/min

Unknown:

Time = ?

Solution:

Speed is the rate of change of distance with time.

  it is mathematically expressed as;

     speed = \frac{distance }{time}

Initial time using speed 350m/min can be calculated by making time the subject of the formula;

     time taken = \frac{distance }{speed}

    time taken at speed of speed of 350m/min = \frac{3150}{350} = 9min

   to seconds = 9 x 60 = 540 seconds

  time taken at speed of 375m/min = \frac{3150}{375} = 8.4min

   to seconds = 8.4 x 60 = 504 seconds.

It could have taken 504 seconds sooner saving 36 seconds.

learn more:

Speed brainly.com/question/10177389

#learnwithBrainly

7 0
3 years ago
Round off the following measurement to three significant figures. 1.296 g
REY [17]
It would be 1 or 2 because if the number is higher than 5 you need to round up , if its lower than 5 you need to round down.

7 0
3 years ago
2. Which of the following elements does not lose an electron easily? (a) Na (6) F (c) Mg (d) Al​
vaieri [72.5K]

Answer:

Answer: (b) F

Explanation:

Sodium has 1, magnesium has 2 and Aluminium has 3 electrons in its outermost shell whereas Fluorine has 7 electrons in its outermost shell hence Fluorine does not lose electrons easily.

The electronic configuration of fluorine is 2,7.

Fluorine is the ninth element with a total of 9 electrons.

The first two electrons will go in the 1s orbital.

The next 2 electrons for F go in the 2s orbital.

The remaining five electrons will go in the 2p orbital. Therefore the F electron configuration will be 1s22s22p5.

3 0
2 years ago
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