Answer:
a. E = 86.36 x 10⁻³ V/m = 86.36 mV/m
b. ρ = 3.6 x 10⁻⁷ Ωm
Explanation:
a.
The electric field in terms of the voltage is given by the following formula:
E = V/d
where,
E = Electric Field in the Wire = ?
V = Potential Difference = 3.8 V
d = distance between the points = 44 m
Therefore,
E = 3.8 V/44 m
<u>E = 86.36 x 10⁻³ V/m = 86.36 mV/m</u>
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b.
Now, from Ohm's Law:
V = IR
R = V/I
where,
R = Resistance of wire = ?
I = Current = 3 A
Therefore,
R = 3.8 V/3 A
R = 1.27 Ω
Now, the resistance of a wire can be given as:
R = ρL/A
where,
ρ = resistivity of material = ?
L = Length = 44 m
A = Cross-sectional area = πr² = π(0.002 m)² = 1.25 x 10⁻⁵ m²
Therefore,
1.27 Ω = ρ*44 m/1.25 x 10⁻⁵ m²
(1.27 Ω)(1.25 x 10⁻⁵ m²)/44 m = ρ
<u>ρ = 3.6 x 10⁻⁷ Ωm</u>
Pluto has a shape that is nearly round, and it orbits the Sun. It has five known moons. It is called a dwarf planet and not a planet because its orbit is not cleared of like-sized or larger objects
Answer: Option B
<u>Explanation:</u>
According to the International Astronomical Union (IAU), Pluto has been mentioned as Dwarf Planet as it doesn't hold the standardisation to be counted as a Planet.
According to the standard criteria, a planet must have been surrounded by the orbit of the Sun, it must have significant mass to have a gravitational pull and hence, circular shape, and should have isolated surrounding.
But, Pluto has various celestial bodies in its vicinity that are larger in size. Hence, as concluded by the Union, any celestial body that does not has clear surrounding, is regarded as Dwarf Planet just like Pluto.
The horizontal component of the force is 173.2 N.
The vertical component of the force is 100 N.
The given parameters:
- Applied force, F = 200 N
- Angle of inclination, Ф = 30⁰
<h3>Horizontal component of the force</h3>
The horizontal component of the force is calculated as follows;
<h3>Vertical component of the force</h3>
The vertical component of the force is calculated as follows;
Learn more about components of forces here: brainly.com/question/8106035
Answer:
0.1 m
Explanation:
The closest distance the electrodes used in an NCV test in oerder to measure
the voltage change as a response to the stimulus is 0.1 m.
This is because the shortest observable time period is not less than the action-potential time response of 1 mili second the length traveled by the sensation during this time is 1 m sec x 100 m / s =0.1 m, which is the shortest distance the electrodes could be positioned on the nerve.
