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Sophie [7]
2 years ago
6

As amplitude of a wave increases, the

Physics
1 answer:
agasfer [191]2 years ago
7 0

i think so it is frequency

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You place a +1.00 mC charged object in an electric field of 900 N/C that points due East. Determine the magnitude and direction
Kay [80]

Answer:

0.9 N, east

Explanation:

charge, q = 1 mC = 0.001 C

Electric filed, E = 900 N/C due east

Force, F = q E

F = 0.001 x 900

F = 0.9 N

The direction of force is same as the direction of electric field as the charge is positive in nature. So, the direction of force is also east.

3 0
3 years ago
What is the drawback to use period of pendulum as time standard
Vadim26 [7]

The time period of a simple pendulum depends upon its length and value of'g'at any place. The period of the pendulum of fixed length

3 0
3 years ago
Your favorite radio station broadcasts at a frequency of 91.5 MHz with a power of 11.5 kW. How many photons does the antenna of
Elena-2011 [213]

Answer:

Number of photons emit per second = 1.9 × 10²⁹  (Approx)

Explanation:

Given:

Frequency = 91.5 MHz

Power = 11.5 Kw = 11,500 J/s

Find:

Number of photons emit per second

Computation:

Total energy with frequency (E) = hf

Total energy with frequency (E) = 6.626×10⁻³⁴  × 91.5×10⁶

Total energy with frequency (E) = 6.06×10⁻²⁶ J

Number of photons emit per second = 11,500 / 6.06×10⁻²⁶

Number of photons emit per second = 1897.689 × 10²⁶

Number of photons emit per second = 1.9 × 10²⁹  (Approx)

5 0
3 years ago
A new planet has been discovered and given the name Planet X . The mass of Planet X is estimated to be one-half that of Earth, a
harina [27]

Answer:

    vₐ = v_c  ( \ 1 + \frac{1}{2} ( \frac{\Delta M}{M} - \frac{\Delta R}{R}) \ )

Explanation:

To calculate the escape velocity let's use the conservation of energy

starting point. On the surface of the planet

          Em₀ = K + U = ½ m v_c² - G Mm / R

final point. At a very distant point

         Em_f = U = - G Mm / R₂

energy is conserved

           Em₀ = Em_f

           ½ m v_c² - G Mm / R = - G Mm / R₂

           v_c² = 2 G M (1 /R -  1 /R₂)

if we consider the speed so that it reaches an infinite position R₂ = ∞

           v_c = \sqrt{\frac{2GM}{R} }

now indicates that the mass and radius of the planet changes slightly

            M ’= M + ΔM = M ( 1+ \frac{\Delta M}{M} )

            R ’= R + ΔR = R ( 1 + \frac{\Delta R}{R} )

we substitute

           vₐ = \sqrt{\frac{2GM}{R} } \  \frac{\sqrt{1+ \frac{\Delta M}{M} } }{ \sqrt{1+ \frac{ \Delta R}{R} } }

         

let's use a serial expansion

           √(1 ±x) = 1 ± ½ x +…

we substitute

         vₐ = v_ c ( (1 + \frac{1}{2}  \frac{\Delta M}{M} )  \ ( 1 - \frac{1}{2}  \frac{\Delta R}{R} ))

we make the product and keep the terms linear

        vₐ = v_c  ( \ 1 + \frac{1}{2} ( \frac{\Delta M}{M} - \frac{\Delta R}{R}) \ )

5 0
2 years ago
Two equal resistors are connected in series with a 1.50V battery. In order to keep the current at 0.030 A, the resistors much ea
AlexFokin [52]

Answer: 25 Ohms

Explanation:

From this question, the following parameters are given:

Voltage V = 1.5 v

Current I = 0.03A

From Ohm's law;

V = IR

Where R = resultant resistance of the two resistors.

Substitute V and I into the formula and make resultant R the subject of formula.

1.5 = 0.03 × R

R = 1.5/0.03

R = 50 Ohms

From the question, it is given that Thr two equal resistors are connected in series.

R = R1 + R2

But R1 = R2

50 = 2R1

R1 = 50/2

R1 = 25

R1 = R2 = 25 Ohms

Therefore, the resistors must each have a value of 25 Ohms

4 0
3 years ago
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