All categories

2 years ago

What are the values of a 1 and r of the geometric series? 1 + 3 + 9 + 27 + 81

Mathematics

2 answers:

hammer [34]2 years ago

4 0

Answer:

a₁ = 1; r = 3

Step-by-step explanation:

a₁ represents the first term. It is 1 in this case.

r represents the common ratio between terms. In this case it's 3 / 1 = 3.

zysi [14]2 years ago

3 0

Answer:

a1 = 1

r = 3

Step-by-step explanation:

a1 = first term = 1

r = common ratio = 2nd term/1st term

= 3/1

r = 3

You might be interested in

A boat travelled 336 km downstream with the current. The trip downstream took 12 hours.

miskamm [114]

Answer:

We know the distance (d) equation in terms of rate (r) and time (t) as:

d=rt

Step-by-step explanation:

We have given d=336 km and t= 12 hours, so we have: 336 km = 12t <-- this is our equation.

Divide each side by 12 to solve for t:

12t/12=336/12

t= 28 km/ hour

5 0

2 years ago

If f(x) = │(x² – 50)│, what is the value of f(-5) ?

Liula [17]

$f(x)=|(x^2-50)|\\\\f(-5)=|(-5)^2-50|=|25-50|=|-25|=25\\\\\\|a|= \left\{\begin{array}{ccc}a&for&a\geq0\\-a&for&a < 0\end{array}\right\\\\|-3|=3;\ |5|=5;\ |0|=0;\ |-12|=12$

5 0

3 years ago

Read 2 more answers

The temperature at 9 p.m. was 12°F. The temperature dropped 15°F by 5 a.m.The temperature at 5 a.m. was

satela [25.4K]

The temperature at 5 am was -3 degrees

12-15=-3

4 0

2 years ago

Please solve with explanation

Juliette [100K]

Step-by-step explanation:

$4\frac{9}{20} - 1\frac{2}{6} =\\\frac{89}{20} - \frac{8}{6} = \frac{89 - 26.7}{20} = \frac{62.3}{20} \\$

$4\frac{6}{9} - 3\frac{3}{6} =\\\frac{42}{9} - \frac{21}{6} = \frac{252 - 189}{54} = \frac{63}{54} = 1\frac{9}{54}$

$2\frac{2}{4} - 1\frac{1}{3} =\\\frac{10}{4} - \frac{4}{3} = \frac{30 - 16}{12} = \frac{14}{12} = 1\frac{2}{12}$

8 0

3 years ago

Read 2 more answers

Determine whether f(x) = –5x^2 – 10x + 6 has a maximum or a minimum value.

Blizzard [7]

First,

We are dealing with parabola since the equation has a form of,

$y=ax^2+bx+c$

Here the vertex of an up - down facing parabola has a form of,

$x_v=-\dfrac{b}{2a}$

The parameters we have are,

$a=-5,b=-10, c=6$

Plug them in vertex formula,

$x_v=-\dfrac{-10}{2(-5)}=-1$

Plug in the $x_v$ into the equation,

$y_v=-5(-1)^2-10(-1)+6=11$

We now got a point parabola vertex with coordinates,

$(x_v, y_v)\Longrightarrow(-1,11)$

From here we emerge two rules:

If $a$ then vertex is max value
If $a>0$ then vertex is min value

So our vertex is minimum value since,

$a=-5\Longleftrightarrow a$

Hope this helps.

r3t40

7 0

2 years ago