Answer:
a^2 - b^2 = (a+b)(a-b) where a = X and b = 6
(X+6)(X-6)
Hope this helps(:
Step-by-step explanation:
Solving a system of equations, we will see that there are 6000 kg of coal on the pile.
<h3>
How many kilograms of coal are in the pile of coal?</h3>
Let's say that there are N kilograms of coal, and it is planned to burn it totally in D days, these are our variables.
We know that:
- If the factory burns 1500 kilograms per day, it will finish burning the coal one day ahead of planned.
- If it burns 1000 kilograms per day, it will take an additional day than planned.
Then we can write the system of equations:
(1500)*(D - 1) = N
(1000)*(D + 1) = N
Because N is already isolated in both sides, we can write this as:
(1500)*(D - 1) = N = (1000)*(D + 1)
Then we can solve for D:
(1500)*(D - 1) = (1000)*(D + 1)
1500*D - 1500 = 1000*D + 1000
500*D = 2500
D = 2500/500 = 5
Now that we know the value of D, we can find N by replacing it in one of the two equations:
(1500)*(D - 1) = N
(1500)*(5 - 1) = N
(1500)*4= N = 6000
This means that there are 6000 kilograms of coal on the pile.
If you want to learn more about systems of equations:
brainly.com/question/13729904
#SPJ1
105 divided by 6 equals 17. 5
She should buy 18 packages
Alright so the answer would be letter B, because
win-to-loss
49 to 21 (You can determine her losses by subtracted the number of wins from her total number of games played)
Now you must simplify your answer
7 is the greatest common factor (GCF) of both 49 and 21
Now divide both 49 and 21 by 7 to get
7 to 3
Answer:
i think so 3/4 If i am wrong plz anyone say the correct answer
