3 years ago

Which electrons are the valence electrons of the atom

Chemistry

2 answers:

DaniilM [7]3 years ago

7 0

Negative electrons not sure that’s right haven’t did that in a while

ad-work [718]3 years ago

5 0

Explanation:

Valence electrons are those electrons found in the outermost shell of an atom. In other words, these are the electrons that can be gained or lost during a chemical reaction.

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Consider the following reaction at equilibrium. What will happen if SO2SO2 is added to the reaction? 4FeS2FeS2(s) + 11O2O2(g) ⇌⇌

kupik [55]

Answer:

The equilibrium will change in the direction of the reactants

Explanation:

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3 years ago

Write a balanced half-reaction describing the reduction of aqueous iron(III) cations to aqueous iron(II) cations.

melamori03 [73]

Answer:

The answer to your question is:

Explanation:

Iron (III) ⇒ Iron (II)

Fe⁺³ + 1e⁻ ⇒ Fe⁺²

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4 years ago

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You have exactly 1.722 x 10^3 eggs. Calculate the dozens of eggs that you have.

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$1.722 \times {10}^{3} = 1722\: eggs$

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3 years ago

Draw a line from each element to the reason for using that element

nataly862011 [7]

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3 years ago

A 100.0-g sample of water at 27.0oC is poured into a 71.0-g sample of water at 89.0oC. What will be the final temperature of the

Sedbober [7]

<u>Answer:</u> The final temperature will be $52.74^oC$

<u>Explanation:</u>

Calculating the heat released or absorbed for the process:

$q=m\times C\times (T_2-T_1)$

In a system, the total amount of heat released is equal to the total amount of heat absorbed.

$q_1=-q_2$

$m_1\times C\times (T_f-T_1)=-m_2\times C\times (T_f-T_2)$ ......(1)

where,

C = heat capacity of water = $4.184J/g^oC$

$m_1$ = mass of water of sample 1 = 100.0 g

$m_2$ = mass of water of sample 2 = 71.0 g

$T_f$ = final temperature of the system = ?

$T_1$ = initial temperature of water of sample 1 = $27^oC$

$T_2$ = initial temperature of the water of sample 2 = $89.0^oC$

Putting values in equation 1, we get:

$100.0\times 4.184\times (T_f-27)=-71.0\times 4.184\times (T_f-89)\\\\171T_f=9019\\\\T_f=\frac{9019}{171}=52.74^oC$

Hence, the final temperature will be $52.74^oC$

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3 years ago