Question

Write a balanced half-reaction describing the reduction of aqueous iron(III) cations to aqueous iron(II) cations.​

Answer 1

Answer:

The answer to your question is:

Explanation:

                  Iron (III)  ⇒ Iron (II)

                  Fe⁺³ + 1e⁻   ⇒   Fe⁺²

                 

Answer 2

Answer: The balanced half reaction is written below.

Explanation:

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

$X^{n+}+ne^-\rightarrow X$

When iron (III) cations is reduced to iron (II) cations, the number of electron transfer is 1.

The chemical equation for the reduction of iron (III) cations follows:

$Fe^{3+}(aq.)+e^-\rightarrow Fe^{2+}(aq.)$

Hence, the balanced half reaction is written above.