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pishuonlain [190]
3 years ago
13

A Sound wave has a frequency of 192 HZ and travels across a football field (91.4m) in 2 seconds. what is the wavelength of the s

ound wave?​
Physics
1 answer:
igor_vitrenko [27]3 years ago
3 0

The wavelength of the sound wave is 0.24 m

Explanation:

First of all, we calculate the  speed of the wave, which is the ratio between the distance covered by the wave and the time taken:

v=\frac{d}{t}

where, for the wave in this problem

d = 91.4 m

t = 2 s

Substituting,

v=\frac{91.4}{2}=45.7 m/s

Now we can find the wavelength of the wave by using the wave equation:

v=f \lambda

where

v is the speed of the wave

f is its frequency

\lambda is the wavelength

For the wave here,

f = 192 Hz

v = 45.7 m/s

Solving for the wavelength,

\lambda = \frac{v}{f}=\frac{45.7}{192}=0.24 m

Learn more about waves:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

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3 years ago
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A loaf of bread (volume 3100 cm3) with a density of 0.90 g/cm3 is crushed in the bottom of the grocery bag into a volume of 1240
andrew11 [14]

Answer:

2,25 g/cm3

Explanation:

Hi, you have to know one thing for this.. Density = mass/Volume,

When you have the loaf of bread with 3100 cm3 and a density of 0.90 g/cm3, the mass of that bread is 2790 g because of if you isolate the variable mass from the equation you get..  mass= density x volume

Later, have on account the mass never changes, so you crush the bread and the mass is the same.. so when you have the mashed bread.. you know that the mass is 2790 g and the volume of the bag is 1240 cm3, so you apply the main equation.... density=2790 g / 1240 cm3 , so density =  2,25 g/cm3

8 0
3 years ago
Which of the following options is correct and why?
Dimas [21]

Answer:

Option (e) = The charge can be located anywhere since flux does not depend on the position of the charge as long as it is inside the sphere.

Explanation:

So, we are given the following set of infomation in the question given above;

=> "spherical Gaussian surface of radius R centered at the origin."

=> " A charge Q is placed inside the sphere."

So, the question is that if we are to maximize the magnitude of the flux of the electric field through the Gaussian surface, the charge should be located where?

The CORRECT option (e) that is " The charge can be located anywhere since flux does not depend on the position of the charge as long as it is inside the sphere." Is correct because of the reason given below;

REASON: because the charge is "covered" and the position is unknown, the flux will continue to be constant.

Also, the Equation that defines Gauss' law does not specify the position that the charge needs to be located, therefore it can be anywhere.

6 0
3 years ago
A meter stick is held vertically above your hand, with the lower end between your thumb and first finger. On seeing the meter st
inessss [21]

Answer:

t=0.193s

Explanation:

What is said is that the meter fell d=18.3cm=0.183m under the action of gravity. We can use the formula for accelerated motion:

d=v_0t+\frac{at^2}{2}

Since it departed from rest it will mean that:

d=\frac{at^2}{2}

So our time will be:

t=\sqrt{\frac{2d}{a}}

Which for our values is:

t=\sqrt{\frac{2(0.183m)}{(9.81m/s^2)}}=0.193s

7 0
3 years ago
A nuclear fission power plant has an actual efficiency of 32%. If 0.18 MW of power are produced by the nuclear fission, how much
7nadin3 [17]

Answer:

 P₀ = 5.76 x 10⁻² MW

Explanation:

given,

efficiency of the power plant = 32%

Power produced by the nuclear fission = 0.18 MW

the power plant output = ?

using formula of efficiency

\eta = \dfrac{P_0}{P}

where P is the power produced in the power plant

          P₀ is the power output of the power plant

\eta = \dfrac{P_0}{P}

0.32 = \dfrac{P_0}{0.18}

 P₀ = 0.18 x 0.32

 P₀ =  0.0576 MW

 P₀ = 5.76 x 10⁻² MW

Power plant output is equal to  P₀ = 5.76 x 10⁻² MW

8 0
3 years ago
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