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3 years ago

Helppppppppppppppppppppppppppppppppp

Mathematics

1 answer:

jarptica [38.1K]3 years ago

5 0

The answer is C, about 26 mins.

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Which math problem is being modeled on the number line

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Well, both variables appear to be negative, and the only option present that equals -20 is option A

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3 years ago

Evaluate sin^2Θ, for Θ=45°

Zielflug [23.3K]

Answer:

sin^2(45) = (√2/2)^2 = 1/2

Step-by-step explanation:

sin2x = sin2 * x = 0.909x

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Hope this helps.

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3 years ago

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A model car is 8 inches long and 5.2

Sphinxa [80]

Use proportions here - 8/5.2 = 96/width of actual car. using cross multiplication, 5.2*96 = 8x. this gives you 499.2 = 8x. divide both sides by eight to get x=62.4. the width of the actual car is 62.4 inches.

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2 years ago

John Gray bought a basic car for $32,750.00, with options that cost $375.00. There's a 6% sales tax in his state and a combined

Andreas93 [3]

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3 years ago

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In an insect colony there are 270 insects after 9 days. If there were initially 80 insects how long will it take the population

Semenov [28]

Answer:

The time it will take the population to grow to 800 insects is 17 days.

Step-by-step explanation:

The growth function of the insects is exponential.

The exponential growth function is:

$y=a(1+r)^{t}$

Here,

y = final value

a = initial value

r = growth rate

t = time taken

It is provided that there were 270 insects after 9 days and initially there were 80 insects.

Compute the value of r as follows:

$y=a(1+r)^{t}\\\\270=80(1+r)^{9}\\\\3.375=(1+r)^{9}\\\\\ln(3.375)=9\cdot \ln(1+r)\\\\0.135155=\ln(1+r)\\\\1+r=1.14471\\\\r=0.145$

Now, compute the time it will take the population to grow to 800 insects as follows:

$800=80(1+0.145)^{t}\\\\10=(1.145)^{t}\\\\\ln(10)=t\cdot \ln(1.145)\\\\t=17.00522\\\\t\approx 17$

Thus, the time it will take the population to grow to 800 insects is 17 days.

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3 years ago