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Mama L [17]
3 years ago
7

An understanding of periodic trends is important because the trends 1. can be used to convert non-useful elements to useful ones

. 2. allow compounds to be broken into their elements. 3. relate to properties of elements and how they may react. 4. allow prediction of electron configurations and bond orders.
Chemistry
1 answer:
Andreas93 [3]3 years ago
8 0
<span>3. relate to properties of elements and how they may react. Periodic trends are specific patterns that are present in the periodic table that include size, electronic properties, melting point, electronegativity and metallic character. The trends exist due to the similar atomic structure of the elements within each group family.</span>
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Write reaction equations to explain how your acetic acid-acetate buffer reacts with an acid and reacts with a base.
guajiro [1.7K]

acetic acid = CH3COOH(aq) , acetate = CH3COO-(aq) and proton = H+(aq)

so...

CH3COOH(aq) <-> CH3COO-(aq) + H+(aq)

this is the dissociation of acid, therefore, it will yield H+ ions in solution, which are ACIDIC

then... for the acetate buffer, recall that

CH3COO-(aq) is a weak conjugate base, so, it can accept H+ if in excess

so

H+(aq) + CH3COO-(aq) <--> CH3COOH(aq)

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Addition of OH- ins, from a strong base:

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4 years ago
What chemical destroys protiens
natima [27]

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3 0
3 years ago
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Describe what you can do to reduce non-point source water pollution. List at least 3 specific actions, or, write 3 sentences abo
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3 years ago
What is the total pressure in atmospheres in a 10.0L vessel containing 2.50 x 10-3 mol H2, 1.00 x 10-3
grigory [225]

Answer:

Total pressure = 16.42× 10⁻⁹atm

Explanation:

Given data:

Moles of H₂ = 2.50 × 10⁻³ mol

Moles of He = 1.00 × 10⁻³ mol

Mass of Ne = 3 × 10⁻⁴ mol

Volume = 10 L

Temperature = 35°C

Total pressure = ?

Solution:

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P = nRT / V

P = 2.50 × 10⁻³ mol× 0.0821 atm. L.mol⁻¹ .k⁻¹ × 308 K / 10 L

p = 63.22× 10⁻³  atm. L /10 L

P = 6.3 × 10⁻³atm

Pressure of helium:

P = nRT / V

P = 1.00 × 10⁻³ mol× 0.0821 atm. L.mol⁻¹ .k⁻¹ × 308 K / 10 L

p = 25.29 × 10⁻³ atm. L /10 L

P = 2.53× 10⁻³ atm

Pressure of neon:

P = nRT / V

P = 3 × 10⁻⁴ mol× 0.0821 atm. L.mol⁻¹ .k⁻¹ × 308 K / 10 L

p = 75.86× 10⁻³ atm. L /10 L

P = 7.59× 10⁻³ atm

Total pressure of mixture:

P(mixture)  = pressure of hydrogen + pressure of helium+ pressure of neon

P(mixture)  = 6.3 × 10⁻³atm + 2.53× 10⁻³ atm + 7.59× 10⁻³ atm

P(mixture) = 16.42× 10⁻⁹atm

8 0
3 years ago
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