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Mama L [17]
3 years ago
7

An understanding of periodic trends is important because the trends 1. can be used to convert non-useful elements to useful ones

. 2. allow compounds to be broken into their elements. 3. relate to properties of elements and how they may react. 4. allow prediction of electron configurations and bond orders.
Chemistry
1 answer:
Andreas93 [3]3 years ago
8 0
<span>3. relate to properties of elements and how they may react. Periodic trends are specific patterns that are present in the periodic table that include size, electronic properties, melting point, electronegativity and metallic character. The trends exist due to the similar atomic structure of the elements within each group family.</span>
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In order for rock formations to move the plates__________ .
ANEK [815]
Igneous rocks are found where plates diverge, as lava rises and fills the gap between the plates. Igneous rocks also form where plates converge. The subducting plate melts as it sinks into the crust of the Earth, and the melt rises into the overriding plate forming volcanoes.
4 0
3 years ago
What is the MOLAR heat of combustion of methane(CH₄) if 64.00g of methane are burned to heat 75.0 ml of water from 25.00°C to 95
melamori03 [73]

Answer:

-5.51 kJ/mol

Explanation:

Step 1: Calculate the heat required to heat the water.

We use the following expression.

Q = c \times m \times \Delta T

where,

  • c: specific heat capacity
  • m: mass
  • ΔT: change in the temperature

The average density of water is 1 g/mL, so 75.0 mL ≅ 75.0 g.

Q = 4.184J/g.\°C \times 75.0g \times (95.00\°C - 25.00\°C) = 2.20 \times 10^{3} J = 2.20 kJ

Step 2: Calculate the heat released by the methane

According to the law of conservation of energy, the sum of the heat released by the combustion of methane (Qc) and the heat absorbed by the water (Qw) is zero

Qc + Qw = 0

Qc = -Qw = -22.0 kJ

Step 3: Calculate the molar heat of combustion of methane.

The molar mass of methane is 16.04 g/mol. We use this data to find the molar heat of combustion of methane, considering that 22.0 kJ are released by the combustion of 64.00 g of methane.

\frac{-22.0kJ}{64.00g} \times \frac{16.04g}{mol} = -5.51 kJ/mol

8 0
3 years ago
we can determine the velocity of a wave when given the _______ and the wavelength. (2 points) frequency amplitude crest equilibr
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Frequency.

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6 0
3 years ago
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Answer:

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Farm or residential tank of capacity more than 11 gallons used for storing motor fuel is covered by federal regulations regarding USTs.

According to the given question,

Only Harry and Jena are covered by federal regulations regarding USTs.

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3 years ago
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Answers:
______________________________________________
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