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Arada [10]
3 years ago
13

At STP, a 50.-gram sample of H2O(l) and a 100.-gram sample of H2O(1) have

Chemistry
1 answer:
LiRa [457]3 years ago
6 0

Answer:

The same chemical properties

Explanation:

Different masses of water at the same temp and pressure will have different volumes and the same empirical formulas and the same chemical properties

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Hundreds of years ago, it was believed by many that our solar system was Geocentric. This means that Earth is at the center of t
Artyom0805 [142]

Answer:

B) Earth and all the other planets orbit the Sun.

Explanation:

A) This one is basically what people used to think, that the sun and other planets orbited around Earth. We know now that this is not true.

C) We know that no planets orbit around Earth.

D) The Sun does not orbit around Earth, the Earth orbits around the Sun.

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3 years ago
This group of fungi forms spores in a round structure on the end of a hyphae
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Is zygote fungi an option??

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2 years ago
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2 SO3 (g) + Heat <-----> 2 SO2 (g) + O2 (g)
Step2247 [10]

Answer:

The concentration of SO₂ will decreases

Explanation:

As you can see in the reaction

2 moles of gas ⇆ 3 moles of gas

Based on Le Châtelier's principle, a change doing in a system will produce that the system reacts in order to counteract the change made.

If the pressure is increased, the system will shift to the left in order to produce less moles of gas and decrease, thus, the pressure.

As the system shift to the left, the concentration of SO₂ will decreases

7 0
3 years ago
What is the product of the reaction between arsenic and oxygen
Ivan

Answer:

d

Explanation:

As + O2 -------->as2o3

5 0
3 years ago
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A 7.06% aqueous solution of sodium bicarbonate has a density of 1.19g/mL at 25°C what is the molarity and molality of the soluti
lilavasa [31]

<em>c</em> = 1.14 mol/L; <em>b</em> = 1.03 mol/kg

<em>Molar concentration </em>

Assume you have 1 L solution.

Mass of solution = 1000 mL solution × (1.19 g solution/1 mL solution)

= 1190 g solution

Mass of NaHCO3 = 1190 g solution × (7.06 g NaHCO3/100 g solution)

= 84.01 g NaHCO3

Moles NaHCO3 = 84.01 g NaHCO3 × (1 mol NaHCO3/74.01 g NaHCO3)

= 1.14 mol NaHCO3

<em>c</em> = 1.14 mol/1 L = 1.14 mol/L

<em>Molal concentration</em>

Mass of water = 1190 g – 84.01 g = 1106 g = 1.106 kg

<em>b</em> = 1.14 mol/1.106 kg = 1.03 mol/kg

5 0
3 years ago
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