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evablogger [386]
4 years ago
8

Consider this question: What mass of concentrated solution nitric acid( 68.0% HNO3 by mass) is needed to prepare 400.0 g of a 10

.0% solution of HNO3 by mass?
(a) Outline the steps necessary to answer the question
(b) Answer the question
Chemistry
1 answer:
Elena L [17]4 years ago
8 0

<u>Answer:</u> The mass of concentrated nitric acid solution required is 58.82 g

<u>Explanation:</u>

To calculate the mass of concentrated solution, we use the equation:

c_1m_1=c_2m_2

where,

c_1\text{ and }m_1 are the concentration and mass of concentrated solution.

c_2\text{ and }m_2 are the concentration and mass of diluted solution.

We are given:

c_1=68\%\\m_1=?g\\c_2=10\%\\m_2=400g

Putting values in above equation, we get:

68\times m_1=10\times 400\\\\m_1=58.82g

Hence, the mass of concentrated nitric acid solution required is 58.82 g

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A compound has a molecular formular of C12H24O6.What is the compound's empirical formula ​
scoundrel [369]

Answer:

The empirical formula for C12 H24 O6 is C2 H4 O.

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You have 15 grams of ice at 0°C. How much energy is needed to melt the ice and warm it to 25°C. Ice melts at 0°C. The specific h
azamat

Answer:

d. 1600 calories

Explanation:

The heat of fusion of water, L, is the amount of heat per gram required to melt the ice to water, a process which takes place at a constant temperature of 0 °C. The specific heat of water, c, is the amount of heat required to change the temperature of 1 gram of water by 1 degree Celsius.

We will convert the units of c from Jg⁻¹°C⁻¹ to cal·g⁻¹°C⁻¹ since the answers are provided in calories. The conversion factor is 4.18 J/cal.

(4.18 Jg⁻¹°C⁻¹)(cal/4.18J) = 1 cal·g⁻¹°C⁻¹

First we calculate the heat required to melt the ice, where M is the mass:

Q = ML = (15 g)(80 cal/g) = 1200 cal

Then, we calculate the heat required to raise the temperature of water from 0 °C to 25 °C.

Q = mcΔt = (15 g)(1 cal·g⁻¹°C⁻¹)(25 °C - 0 °C) = 380 cal

The answer is rounded so that there are two significant figures

The total heat required for this process is (1200 cal + 380 cal) = 1580 cal

The rounded answer is 1600 calories.

3 0
3 years ago
Compound X has a molar mass of 316.25 g*mol^-1 and the following composition:
Leokris [45]

Answer:

Compound X has a molar mass of 316.25 g*mol^-1 and the following composition:

element & mass %

phosphorus & 39.18%

sulfur & 60.82%

Write the molecular formula of X.

Explanation:

The given molecule of phosphorus and sulfur has molar mass --- 316.25 g.

Empirical formula calculation:                      

element:              phosphorus                       sulfur

co9mposition:      39.185%                            60.82%

divide with

atomic mass:          39.185/31.0 g/mol           60.82/32.0g/mol

                              =1.26mol                           1.90mol

smallest mole ratio:   1.26mol/1.26mol =1      1.90mol/1.26 mol =1.50

multiply with 2:          2                                         3

Hence, the empirical formula is:

P2S3.

Mass of empirical formula is:

158.0g/mol

Given, molecule has molar mass --- 316.25 g/mol

Hence, the ratio is:

316.25g/mol/158.0 =2

Hence, the molecular formula of the compound is :

2 x (P2S3)

=P_4S_6

8 0
3 years ago
True or false
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Answer:

1. true

2. false

3. true

4. true

Explanation:

I believe these are the answers, I'm just not sure for #3

4 0
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Oksi-84 [34.3K]

Answer:

I believe it is "Arsenenate"

3 0
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