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3 years ago

Please answer the chemistry question shown in the attachment photo! 25 points!

Chemistry

1 answer:

iogann1982 [59]3 years ago

5 0

I’m so sorry if it’s wrong but I think it’s this.....

Answer:

2NaHCO3(s) = Na2CO3(s) + CO2(g) + H2O(g).

And I found it on Quora.com
By the way NaHCO3 is Sodium bicarbonate but a.k.a Baking soda
Hoped this helped :)

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Need help !!!!! ASAP

Ksivusya [100]

<h2>Hello!</h2>

The answer is:

We have that there were produced 0.120 moles of $CO_{2}$

$n=0.120mol$

We are asked to calculate the number of moles of the given gas, also, we are given the volume, the temperature and the pressure of the gas, we can calculate the approximate volume using The Ideal Gas Law.

The Ideal Gas Law is based on Boyle's Law, Gay-Lussac's Law, Charles's Law, and Avogadro's Law, and it's described by the following equation:

$PV=nRT$

Where,

P is the pressure of the gas.

V is the volume of the gas.

n is the number of moles of the gas.

T is the absolute temperature of the gas (Kelvin).

R is the ideal gas constant (to work with pressure in mmHg), which is equal to:

$R=62.363\frac{mmHg.L}{mol.K}$

We must remember that the The Ideal Gas Law equation works with absolute temperatures (K), so, if we are given relative temperatures such as Celsius degrees or Fahrenheit degrees, we need to convert it to Kelvin before we proceed to work with the equation.

We can convert from Celsius degrees to Kelvin using the following formula:

$Temperature(K)=Temperature(C\°) + 273K$

So, we are given the following information:

$Pressure=760mmHg\\Volume=2.965L\\Temperature=25.5C\°=25.5+273K=298.5K$

Now, isolating the number of moles, and substituting the given information, we have:

$PV=nRT$

$n=\frac{PV}{RT}$

$n=\frac{760mmHg*2.965L}{62.363\frac{mmHg.L}{mol.K}*298.5K}$

$n=\frac{760mmHg*2.965L}{62.363\frac{mmHg.L}{mol.K}*298.5K}\\\\n=\frac{2242mmHg.L}{18615.355\frac{mmHg.L}{mol.}}\\\\n=0.120mole$

Hence, we have that there were produced 0.120 moles of $CO_{2}$

$n=0.120mol$

Have a nice day!

7 0

3 years ago

A sample of a compound is determined to have 1.17 g of carbon and 0.287 g of hydrogen. what is the correct representation of the

yarga [219]

CH3 is the empirical formula for the compound.

A sample of a compound is determined to have 1.17g of Carbon and 0.287 g of hydrogen.

The number of atom or moles in the compound is

1.17 g C X 1 mol of C / 12.011 g C = 0.097411 mol of C.

0.287 g H x 1 mol of H / 1 g H = 0.28474 mol H.

This compound contains 0.097411 mol of carbon and 0.28474 mol of Hydrogen.

So we can represent the compound with the formula C0.974H0.284.

Subscripts in formulas can be made into whole numbers by multiplying the smaller subscript by the larger subscript.

we can divide 0.284 by 0.0974.

0.284 / 0.0974 = 3.

So here, Carbon is one and hydrogen is 3.

We can write the above formula as a CH3.

Hence the empirical formula for the sample compound is CH3.

For a detailed study of the empirical formula refer given link brainly.com/question/13058832.

#SPJ1.

5 0

2 years ago

A gate made of painted iron is beginning to rest in areas where the paint has worn away why is the formation of rust considered

Pavel [41]

Answer:

because it is two substances reacting together to create a new substance

Explanation:

when iron rusts, iron molecules react with the oxygen molecules creating iron oxide aka rust.

3 0

3 years ago

In potassium-argon dating, how does the proportion of remaining potassium in a rock or fossil change over time?

lara [203]

Answer:

what was the answer?

Explanation:

8 0

3 years ago

Read 2 more answers

Which of the following has the greatest mass, in grams? 1 atom of lead (Pb) 0.5 mol silver (Ag) atoms 0.3 mol gold (Au) atoms 25

Strike441 [17]

Answer : Option C) 0.3 mol of Gold.

Explanation : Amongst the options given in the question, 0.3 mol of Au is the greatest in mass in grams.

As 0.3 mol X atomic weight of Au (196.966) = 59.088 grams;

Silver has 0.5 mol X atomic weight of Ag (107.86) = 53.93 grams;

The other options are not relevant as they deal in the atomic range which has mass value very less as compared to the moles of elements.

Therefore, it is clear that Au has the greatest mass amongst the given choices.

8 0

4 years ago

Read 2 more answers