All categories

3 years ago

M (2.1) 2. How many moles is 2.55 x 1026 atoms of Neon? 3 Vou bout 20 r.

Chemistry

1 answer:

Olenka [21]3 years ago

6 0

Answer:

423.44 moles

Explanation:

We need to find no of moles in $2.55\times 10^{26}\ \text{atoms}$ of Neon.

We know that,

$1\ \text{mol of atoms}=6.022\times 10^{23}\ \text{atoms}$

$2.55\times 10^{26}\ \text{atoms}=2.55\times 10^{26}\ \text{atoms}\times \dfrac{1\ \text{mol}}{6.022\times 10^{23}\ \text{atoms}}\\\\=423.44\ \text{mol}$

It means there are 423.44 moles in $2.55\times 10^{26}\ \text{atoms}$ of Neon.

You might be interested in

A man heats a balloon in the oven. If the balloon initially has a volume of 0.4 liters and a temperature of 20 degrees celsius,

Airida [17]

Answer:

0.714 liter.

Explanation:

Given:

The balloon initially has a volume of 0.4 liters and a temperature of 20 degrees Celsius.

It is heated to a temperature of 250 degrees Celsius.

Question asked:

What will be the volume of the balloon after he heats it to a temperature of 250 degrees Celsius ?

Solution:

By using:

$PV=nRT$

Assuming pressure as constant,

V∝ T

Now, let K is the constant.

V = KT

Let initial volume of balloon , $V_{1}$ = 0.4 liter

1000 liter = 1 meter cube

1 liter = $\frac{1}{1000} m^{3} = 10^{-3} m^{3$

0.4 liter = $0.4\times10^{-3}=4\times10^{-4} m^{3}$

And initial temperature of balloon, $T_{1}$ = 20°C = (273 + 20)K

= 293 K

Let the final volume of balloon is $V_{2}$

And a given, final temperature of balloon, $T_{2}$ is 250°C = (273 + 250)K

= 523 K

Now, $V_{1}$ = $KT_{1}$

$4\times10^{-4}=K\times293\ (equation\ 1 )$

$V_{2}$ = $KT_{2}$

$=K\times523\ (equation 2)$

Dividing equation 1 and 2,

$\frac{4\times10^{-4}}{V_{2} } =\frac{K\times293}{K\times523}$

K cancelled by K.

By cross multiplication:

$293V_{2} =4\times10^{-4} \times523\\V_{2} =\frac{ 4\times10^{-4} \times523\\}{293} \\ = \frac{2092\times10^{-4}}{293} \\ =7.14\times10^{-4}m^{3}$

Now convert it into liter with the help of calculation done above.

$7.14\times10^{-4} \times1000\\7.14\times10^{-4} \times10^{3} \\0.714\ liter$

Therefore, the volume of the balloon be after he heats it to a temperature of 250 degrees Celsius is 0.714 liter.

5 0

3 years ago

A substance that speeds up a chemical reaction without being part of the chemical change, itself:

allochka39001 [22]

It is known as a catalyst

6 0

3 years ago

1. For a mixture of pure hexane and pure dimethylformamide, the dimethylformamide layer will be found as:______.a. the top layer

castortr0y [4]

Answer:

1. the bottom layer

2. aqueous HCI

3. the top layer

4.aqueous NaOH

5. mostly in the diethyl ether layer

Explanation:

Pure dimethylformamide is considerably more polar than hexane hence thee two solutions will form two phases with the pure dimethylformamide as the bottom layer.

If we want to extract aniline from chloroform, HCl must be added in order to give a salt that can be extracted into the aqueous layer.

For a mixture of methylene chloride and diethyl ether, the diethyl ether layer will be found as the top layer since it is considerably less polar than methylene chloride.

Benzyl alcohol can be extracted from a solution of chloroform by adding NaOH and extracting it into an aqueous layer.

A large partition coefficient for the extraction of naphthalene into diethyl ether from water means that naphthalene will be found mostly in the diethyl ether layer.

3 0

3 years ago

Elements in the periodic table are arranged in columns or

lutik1710 [3]

Maybe by protons i forgot how to spell it :(

3 0

4 years ago

Read 2 more answers

Which element in each of the following sets would you expect to have the lowest IE₃?

AysviL [449]

Answer:

(a) AL

(b) Sc

(c)Al

Explanation:

Ionization Energy is the energy required to remove electrons from the outer most orbitals of atom.

The higher the electron is on energy level the farther its from nucleus and more loosely bonded thus need lesser energy.

By looking at electron configuration we can figure out which electron will need more energy.

1s², 2s², 2p⁶, 3s², 3p⁶,4s², 3d¹

Na₁₁ ⇒ 1s², 2s², 2p⁶, 3s¹

Mg₁₂ ⇒ 1s², 2s², 2p⁶, 3s²

Al₁₃ ⇒ 1s², 2s², 2p⁶, 3s², 2p¹

Al will have lowest IE₃ as its third electron will be in highest energy level and more loosely bonded to nucleus.

K₁₉⇒1s², 2s², 2p⁶, 3s², 3p⁶,4s²

Ca₂₀⇒1s², 2s², 2p⁶, 3s², 3p⁶,4s²

Sc₂₁⇒1s², 2s², 2p⁶, 3s², 3p⁶,4s², 3d¹

Sc will have lowest IE₃ as its third electron will be in highest energy level and more loosely bonded to nucleus.

Li₃ ⇒ 1s², 2s¹

Al₁₃ ⇒ 1s², 2s², 2p⁶, 3s², 2p¹

B₅ ⇒ 1s², 2s², 2p¹

Al will have lowest IE₃ as its third electron will be in highest energy level and more loosely bonded to nucleus.

3 0

3 years ago

Read 2 more answers