Answer:
It is a sigma bond
Explanation:
Chlorine has an electronic configuration of 1s2 2s2 2p6 3s2 3p5. This means that the outermost n=3 level has seven electrons. Hence one more electron is needed for the octet of outermost electrons to be achieved. As a result of this, chlorine enters into covalent bonding with another chlorine atom to form Cl2.
The outermost 3p electrons of the two chlorine atoms are now shared to form a p-p sigma bond (a single bond). Hence, the Cl2 molecule contains a sigma(single) bond between two chlorine atoms. Hence the answer written above.
Answer: option C) II < III < I
i.e [OH−] < [H3O+] < I
Explanation:
First, obtain the pH value of I and II, then compare both with III.
For I
Recall that pH = -log (H+)
So pH3O = -log (H3O+)
= - log (1x10−5)
= 4
For II
pOH = - log(OH-)
= - log(1x10−10)
= 9
For III
pH = 6
Since, pH range from 1 to 14, with values below 7 to be acidic, 7 to be neutral, above 7 to be alkaline: then, 9 < 6 < 4
Thus, the following solutions from least acidic to most acidic is II < III < I
Answer:
D
Explanation:
The cell is the basic structural, functional and biological unit of all known living organisms. Cells are the smallest unit of life that is classified as a living thing, and are often called the "building blocks of life.
The condensation point of water is the same as the boiling point of water. This occurs at 212 degrees Fahrenheit or 100 degrees Celcius. As you increase water up to end beyond 100 degrees celcius, the water will boil
