Answer:
280 g
Explanation:
Let's consider the decomposition of ammonium nitrate.
NH₄NO₃(s) ⇒ N₂(g) + 0.5 O₂(g) + 2 H₂O(g)
We can establish the following relations:
- The molar mass of NH₄NO₃ is 80.04 g/mol.
- The molar ratio of NH₄NO₃ to N₂ is 1:1.
- The molar mass of N₂ is 28.01 g/mol.
The mass of N₂ produced when 800 g of NH₄NO₃ react is:
Answer= 2 mol/dm^3
Explanation:-
Firstly, we convert the volume, which is in cm^3 to dm^3. To do that divide number in cm^3 by 1000:
100/1000= 0.1 dm^3
Formula for concentration is:
Concentration= No. of moles/ Volume
So,
Concentration= 0.2/0.1
Answer= 2 mol/dm^3
Complete Question:
A certain ionic compound X has a solubility in water of .765g/ml at 5 degrees C. Calculate the mass of X that's dissolved in 3 L of a saturated solution of X in the water at this temp. Be sure your answer has the correct unit symbol and significant digits.
Answer:
2.29 kg
Explanation:
A saturated solution is a solution that has the maximum amount of solute diluted at it, so if more solute is added, it will precipitate. The solutions can also be unsaturated (when more solute can be dissolved) or supersaturated (when there is more solute dissolved than the maximum. It's a very unstable solution).
The saturation is measured by the solubility, which indicates how much mass of the solute can be added to a certain volume of the solvent. So, the solubility (S) is the mass (m) divided by the volume (V).
For a solution with 3 L = 3000 mL,
S = m/V
0.765 = m/3000
m = 3000 * 0.765
m = 2295 g
m = 2.29 kg
V = 75 mL = 0,075 L = 0,075 dm³
C = 2.1M
n = ?
---------------
C = n/V
n = C×V
n = 2.1×0,075
n = 0,1575 mol
--------
mKCl: 39+35.5 = 74,5 g/mol
74,5g --------- 1 mol
Xg ------------- 0,1575 mol
X = 74,5×0,1575
X = 11,73375g KCl
:•)
Molar mass of NaOH = 39.997 g/mol
39.997 g ---------- 6.02x10²³ molecules
g --------------- 2.30x10²² molecules
mass = 2.30x 10²² * 39.997 / 6.02x10²³
mass = 9x199^24 / 6.02x10²³
mass = 15.280 g
hope this helps!
