0.014 liters = 14 milliliters.
Hope it helps!
Answer:
a. 652.68N
b. -2349.65J
c. -3116.12J
d. 5465.77J
e. Zero
Explanation:
a. According to equilibrium of forces, the force of gravity is equal to the sum of the frictional force and force exerted by the man in the opposite direction (since they're both resistant forces).
Fg = Fm + Fr
Fm = Fg - Fr
Fm = mgsin(28°) - umgcos(28°)
u = coefficient of frictional force.
Fm = 330*9.8*sin28 - 0.4*330*9.8*cos28
Fm = 1518.27 - 865.59
Fm = 652.68N
b. Work done by man is:
Wm = -Fm * d
Wm = -652.68 * 3.6
Wm = -2349.65J
c. Work done by friction force:
W(Fr) = -Fr * d
W(Fr) = -865.59 * 3.6
W(Fr) = -3116.12J
d. Work done by gravity:
Wg = Fg * d
Wg = 1518.27 * 3. 6
Wg = 5465.77J
e. Net work done on the piano is:
Work done by friction + work done by gravity + work done by man
= -3116.12 + 5464.77 + (-2349.65)
= 0J
Answer:
a) puck is subjected to both the forces of the hockey sticks in a horizontal direction,
b)the puck does not move since the sum of the forces is zero
c) changing the magnitude or direction of its applied force
Explanation:
a) The puck is subjected to both the forces of the hockey sticks in a horizontal direction, these forces are of equal magnitude and opposite direction since the puck is at rest.
In the direction of the y-axis (perpendicular to the ice) you have the weight of the disk and the normal to this weight that are also in equilibrium.
b) the puck does not move since the sum of the forces is zero, which implies that the forces of the hockey sticks are of equal magnitude and opposite direction.
c) the player has several ways to make the puck move
* slightly changing the angle of the club and therefore the direction of the force, in this case the disc comes out in the direction of this component
* inclined the stick slightly so that the force has a vertical component and the puck jumps in this direction
* Increasing the magnitude of the force so that the puck comes out in the opposite direction to the player
* The worst case, decreasing its force to zero and the disk comes out in its direction by the other force that had the same magnitude.
Answer:
B. blocks 2 & 3.
Explanation:
Block 1 has equal & opposite forces acting on it.
Block 2 has 5N on one side, 3N on the other. It will move in the direction the 5N of force is pushing.
Block 3 has no opposing force.
Answer:
0.85m
Explanation:
Given parameters:
Height of fall = 3.5m
Unknown:
Duration of fall = ?
Solution:
To solve this problem, we apply the right motion equation.
Since we know the height, we can use the equation below;
S = ut + 
S is the height
u is the initial velocity = 0m/s
t is the time
g is the acceleration due to gravity
3.5 = 0 + 
x 9.8 x t²
3.5 = 4.9t²
t² = 
t² = 0.71
t = √0.71 = 0.85m
