Answer:
B)
The magnitude of induced emf in the conducting loop is 0.99 mV.
Explanation:
Rate of increase in magnetic field per unit time = 0.090 T/s
Area of the conducting loop = 110 cm^2 = 0.0110 m^2
Electromagnetic induction is the production of an emf or voltage in a coil of wire due to a changing magnetic field through the coil.
Induced e.m.f is given as:
EMF = (-N*change in magnetic field/time)*Area
EMF = rate of change of magnetic field per unit time * Area
EMF = 0.090 * 0.0110
EMF = 0.00099 V
EMF = 0.99 mV
The lungs art part of The excretory<span> system....
</span><span>somatic nervous system is ..... </span><span>autonomic nervous system<span>....
</span></span>
The process in which organ systems work to maintain a stable internal environment is called homeostasis. Keeping a stable internal environment requires constant adjustments. Here are just three of the many ways that human organ systems help the body maintain homeostasis:
Respiratory system: A high concentration of carbon dioxide in the blood triggers faster breathing. The lungs exhale more frequently, which removes carbon dioxide from the body more quickly.
Excretory system: A low level of water in the blood triggers retention of water by the kidneys. The kidneys produce more concentrated urine, so less water is lost from the body.
Endocrine system: A high concentration of sugar in the blood triggers secretion of insulin by an endocrine gland called the pancreas. Insulin is a hormone that helps cells absorb sugar from the blood.
Answer:
The work flow required by the compressor = 100.67Kj/kg
Explanation:
The solution to this question is obtained from the energy balance where the initial and final specific internal energies and enthalpies are taken from A-17 table from the given temperatures using interpolation .
The work flow can be determined using the equation:
M1h1 + W = Mh2
U1 + P1alph1 + ◇U + Workflow = U2 + P2alpha2
Workflow = P2alpha2 - P1alpha1
Workflow = (h2 -U2) - (h1 - U1)
Workflow = ( 684.344 - 491.153) - ( 322.483 - 229.964)
Workflow = ( 193.191 - 92.519)Kj/kg
Workflow = 100.672Kj/kg
Answer:48 V
Explanation:
Given
Three charged particle with charge
Electric Potential is given by
Distance of 
from 
similarly 
Potential at is
![V_{net}=k[\frac{q_1}{d_1}+\frac{q_2}{d_2}+\frac{q_3}{d_3}]](https://tex.z-dn.net/?f=V_%7Bnet%7D%3Dk%5B%5Cfrac%7Bq_1%7D%7Bd_1%7D%2B%5Cfrac%7Bq_2%7D%7Bd_2%7D%2B%5Cfrac%7Bq_3%7D%7Bd_3%7D%5D)
![V_{net}=9\times 10^9[\frac{50}{10}-\frac{80}{12}+\frac{70}{10}]\times 10^{-9}](https://tex.z-dn.net/?f=V_%7Bnet%7D%3D9%5Ctimes%2010%5E9%5B%5Cfrac%7B50%7D%7B10%7D-%5Cfrac%7B80%7D%7B12%7D%2B%5Cfrac%7B70%7D%7B10%7D%5D%5Ctimes%2010%5E%7B-9%7D)
